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Makovka662 [10]
3 years ago
5

A conducting spherical shell of inner radius r1 and outer radius r2 has a charge Q on it. An additional charge, also Q, is then

added to the sphere. What is the resulting charge per unit area on the outer surface of the sphere?
Physics
1 answer:
ankoles [38]3 years ago
3 0

Answer:

Explanation:

Since the spherical shell is conducting , all the charge will lie on the outer surface .

Total charge

= Q +Q = 2Q

surface area = 4πr₂²

surface charge density = charge / surface area

= 2Q / 4πr₂²

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