☁️ Answer ☁️
annyeonghaseyo!
Your answer is:
"A waterwheel built in Hamah, Syria, has a radius of 20.0 m. If the tangential velocity at the wheel’s edge is 7.85 m/s" -Ggle
Hope it helps.
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Answer:
E=930.84 N/C
Explanation:
Given that
I = 1150 W/m²
μ = 4Π x 10⁻⁷
C = 2.999 x 10⁸ m/s
E= C B
C=speed of light
B=Magnetic filed ,E=Electric filed
Power P = I A
A=Area=4πr² ,I=Intensity




E=930.84 N/C
Therefore answer is 930.84 N/C
Answer:
g = 15.5 m/s²
Explanation:
In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:
h = Vi t + (0.5)gt²
where,
h = height covered by the wrench = 5 m
Vi = Initial Velocity = 0 m/s
t = Time Taken to hit the ground = 0.804 s
g = acceleration due to gravity near the surface of the planet = ?
Therefore,
5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²
g = (5 m)/(0.3232 s²)
<u>g = 15.5 m/s²</u>
Answer:
B
Explanation:
It would be diffrent if on a downward slope but assuming your going straight it would be the smallest student.
Answer:

Explanation:
As we know that charge is always conserved
so here we have
initial total charge = final total charge
also we know that gamma rays are chargeless and massless particles
so we have
charge on deuterium is given as
Q = charge on proton + charge on neutron - charge on gamma
so we have

