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Alecsey [184]
2 years ago
6

a ray of light incident on a mirror, at an angle of 45°. Another mirror is placed at an angle of 45° to the first ones as shown.

Sketch the patch of the ray until it emerges from the two mirrors (2mks) 45° www.www 45° ​
Physics
1 answer:
Gwar [14]2 years ago
3 0

Answer:

If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)

The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite  direction to the  incident ray.

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A waterwheel built in hamah
andreev551 [17]

☁️ Answer ☁️

annyeonghaseyo!

Your answer is:

"A waterwheel built in Hamah, Syria, has a radius of 20.0 m. If the tangential velocity at the wheel’s edge is 7.85 m/s" -Ggle

Hope it helps.

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4 0
3 years ago
The Sun delivers an average power of 1150 W/m2 to the top of the Earth’s atmosphere. The permeability of free space is 4π × 10−7
My name is Ann [436]

Answer:

E=930.84 N/C

Explanation:

Given that

I = 1150 W/m²

μ = 4Π x 10⁻⁷

C = 2.999 x 10⁸ m/s

E= C B

C=speed of light

B=Magnetic filed  ,E=Electric filed

Power  P = I A

A=Area=4πr²  ,I=Intensity

I=\dfrac{CB^2}{2\mu_0}

I=\dfrac{CE^2}{2\mu_0 C^2}

E=\sqrt{{2I\mu_0 C}}

E=\sqrt{{2\times 1150\times 4\pi \times 10^{-7}(2.99792\times 10^8)}}

E=930.84 N/C

Therefore answer is 930.84 N/C

4 0
4 years ago
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 5.00 m above
GenaCL600 [577]

Answer:

g = 15.5 m/s²

Explanation:

In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:

h = Vi t + (0.5)gt²

where,

h = height covered by the wrench = 5 m

Vi = Initial Velocity = 0 m/s

t = Time Taken to hit the ground = 0.804 s

g = acceleration due to gravity near the surface of the planet = ?

Therefore,

5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²

g = (5 m)/(0.3232 s²)

<u>g = 15.5 m/s²</u>

4 0
4 years ago
Q
GalinKa [24]

Answer:

B

Explanation:

It would be diffrent if on a downward slope but assuming your going straight it would be the smallest student.

3 0
3 years ago
In the early universe and in stars, deuterium nuclei are produced from the combination of one proton and one neutron, with the r
poizon [28]

Answer:

Q = q_e = 1.6 \times 10^{-19} C

Explanation:

As we know that charge is always conserved

so here we have

initial total charge = final total charge

also we know that gamma rays are chargeless and massless particles

so we have

charge on deuterium is given as

Q = charge on proton + charge on neutron - charge on gamma

so we have

Q = 1.6 \times 10^{-19}

Q = q_e = 1.6 \times 10^{-19} C

6 0
3 years ago
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