1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Digiron [165]
3 years ago
7

A certain half-reaction has a standard reduction potential E⁰ʀᴇᴅ = 0.83 V. An engineer proposes using this half-reaction at the

anode of a galvanic cell that must provide at least 0.80V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.
(1) Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, write "yes" and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, write "no".
(2) Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, write "yes" and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, write "no".
Chemistry
1 answer:
Leviafan [203]3 years ago
5 0

<u>Answer:</u>

<u>For 1:</u> The minimum standard electrode potential at cathode is -0.03 V

<u>For 2:</u> The maximum standard electrode potential at cathode is 1.63 V

<u>Explanation:</u>

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

We are given:

E^o_{cell} = Standard electrode potential of the cell = 0.80 V

  • <u>For 1:</u>

To make the standard reduction potential at the cathode minimum, we take the standard reduction potential at anode as (0.83 V)

Putting values in above equation, we get:

0.80=E^o_{cathode}-(0.83)\\\\E^o_{cathode}=0.80-0.83=-0.03V

Hence, the minimum standard electrode potential at cathode is -0.03 V

  • <u>For 2:</u>

To make the standard reduction potential at the cathode maximum, we take the standard reduction potential at anode as (-0.83 V)

Putting values in above equation, we get:

0.80=E^o_{cathode}-(-0.83)\\\\E^o_{cathode}=0.80+0.83=1.63V

Hence, the maximum standard electrode potential at cathode is 1.63 V

You might be interested in
Which resource is considered the LEAST renewable resource?
Klio2033 [76]
A coal because coal is one of the most natural items on the list
8 0
3 years ago
Most of the energy from a lower trophic level is converted to
frutty [35]
The correct answer to the question above is heat. Most of the energy from a lower trophic level is converted into heat. When an organism from a higher trophic level consumed an organism from a lower trophic level, it is mostly heat that is being converted to.
5 0
3 years ago
How many moles of gold, Au, are in 3.60 x 10^-5 g of gold?
zlopas [31]
<h3>Answer:</h3>

1.83 × 10⁻⁷ mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.60 × 10⁻⁵ g Au (Gold)

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. Multiply:                            \displaystyle 1.82769 \cdot 10^{-7} \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

4 0
3 years ago
Harim placed 5mL of ethanol into a container that weighs 1 gram using a dropper. He already knew the density of ethanol is 0.78
Aleks04 [339]

Answer:

there it is fella tried on ma own consciousness

8 0
3 years ago
I’m very confused on how to solve this
Bond [772]
Recall that density is Mass/Volume. We are given the mL of liquid which is volume so all we need is mass now. We are given the mass of the granulated cylinder both with and without the liquid, so if we subtract them, we can get the mass of the liquid by itself. So, 136.08-105.56= 30.52g. This is the mass of the liquid. We now have all we need to find the density. So, let’s plug these into the density formula. 30.52g/45.4mL= 0.672 g/mL. This is our final answer since the problem requests the answer in g/mL, but be careful, because some problems in the future may ask for g/L requiring unit conversions. Also note that 30.52 was 4 sigfigs and 45.4 was 3 sigfigs, and so dividing them required an answer that was 3 sigfigs as well, hence why the answer is in the thousandths place
4 0
3 years ago
Other questions:
  • Suppose that at one stage in the reaction, 26.0 mol SO , 2 83.0 mol O2, and 17.0 mol SO3 are present in the reaction vessel at a
    11·1 answer
  • If you take energy away from oxygen, will it turn into water? If not, then what will turn into water if you take away energy fro
    6·1 answer
  • A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant? 2Al(s) + 3CuSO4(aq) →
    11·1 answer
  • (1 point) Hydrogen fluoride (HF) has a lower molecular weight compared to hydrogen chloride (HCl), yet its boiling temperature i
    13·1 answer
  • Explain what states are changing in these examples
    14·1 answer
  • What is produced during the replacement reaction of Cu(NO3)2 and Zn?
    11·1 answer
  • Which of the following refers to the horizontal rows of the periodic table?
    13·1 answer
  • Select True or False.<br> The Sun is like the stars we see at night.<br> False<br> True
    13·2 answers
  • Defferent between crysttiline solid and amerphus solid​
    12·2 answers
  • Chem Stoichiometry, questions in Pic<br><br> Thanks )
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!