The sun’s gravitational attraction and the planet’s inertia keeps planets moving is circular orbits.
Explanation:
The planets in the Solar System move around the Sun in a circular orbit. This motion can be explained as a combination of two effects:
1) The gravitational attraction of the Sun. The Sun exerts a force of gravitational attraction on every planet. This force is directed towards the Sun, and its magnitude is

where
G is the gravitational constant
M is the mass of the Sun
m is the mass of the planet
r is the distance between the Sun and the planet
This force acts as centripetal force, continuously "pulling" the planet towards the centre of its circular orbit.
2) The inertia of the planet. In fact, according to Newton's first law, an object in motion at constant velocity will continue moving at its velocity, unless acted upon an external unbalanced force. Therefore, the planet tends to continue its motion in a straight line (tangential to the circular orbit), however it turns in a circle due to the presence of the gravitational attraction of the Sun.
Learn more about gravity:
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Acceleration = velocity / time.
<h3><u>Answer;</u></h3>
Are moving up and down.
As a transverse wave travels through a rope from left to right, the parts of the rope <u>are moving up and down</u>.
<h3><u>Explanation;</u></h3>
- Transverse waves occur when a disturbance causes oscillations perpendicular to the propagation, that is the direction of energy transfer.
- <em><u>Particles of the medium move perpendicular to the direction the transverse wave itself is moving. For example, if the wave is moving to the right, the particles of the medium are moving up and down.</u></em>
- <em><u>Therefore, as a transverse wave travels through a rope from left to right, the parts of the rope are moving up and down.</u></em>
Work:
1 kilometer = 1000 meters
45 × 60 = 2700
W = F × D
W = 2,000 N × 1,000 m
W = 2,000,000 J
P = W ÷ t
P = 2,000,000 J ÷ 2,700 s
P = 741 watts
Answer:
741 watts of horse power.
The cross section is the little tiny circle you see when you cut a wire
and look at the flat, cut end.
The cross-sectional area of the wire is the area of that little circle.
It's equal to
Area = (pi) x (1/4) x (Diameter of the wire)²