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Answer:
What procedure did you use to complete the lab?
→Procedures that needs to be considered to complete the lab are- a thorough knowledge of lab assignments, knowledge about safety equipment, reviewing the MSDS of chemicals for lab experiment etc.
<h3>Explanation:</h3>
To be lab prepared one must follow these procedures-
1. One should have the knowledge of lab assignments to make the lab experiment easier.
2. To be aware about safety equipment and their uses in lab, like- the location of fire extinguisher in lab.
3. To know the steps of experiments to be performed
4. To fill notebook of lab with information regarding the experiment
5. One should review the data sheets of chemicals material safety.
6. To put on all the necessary dressings to perform experiment.
7. To have complete understanding about the experiment disposals.
21) Ionic
22) Ionic
23) Covalent
24) Ionic ?
25) Ionic
26) Ionic
27) Ionic ?
28) Covalent
29) Ionic ?
30) Covalent
31) Ionic ?
32) Ionic ?
33) Covalent
34) Ionic ?
35) Ionic ?
36) Covalent ?
37) Covalent
38) Ionic ?
39) Ionic ?
40) Covalent
These answers are based on if there was a nonmetal and nonmetal it’s Covalent and if there was a metal and nonmetal it was Ionic I didn’t use the electro negativity for the answers that has more than two elements, if the answers had more than two elements they have a ? Next to their answer.
I HOPE THIS HELPS AND IF IM WRONG FEEL FREE TO COMMENT AND TELL ME SO
The new temperature of the piece of lead will be 37.5°C
SPECIFIC HEAT CAPACITY:
- The amount of heat absorbed or released by a substance can be calculated by using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or released (J)
m = mass of substance (g)
c = specific heat capacity
∆T = change in temperature (°C)
According to this question,
Q = 1.90J
m = 1.29g
T1 = 26°C
T2 = ?
c = 0.128 J/g°C
1.90 = 1.29 × 0.128 × (T2- 26°C)
1.90 = 0.165 (T2 - 26°C)
1.90 = 0.165T2 - 4.29
1.90 + 4.29 = 0.165T2
6.19 = 0.165T2
T2 = 37.5°C
Therefore, the new temperature of the piece of lead will be 37.5°C.
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