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3 years ago

What are three ways a fossil can be destroyed after it has formed.

1 answer:

4 0

The three ways in which a fossil can be destroyed after it has been formed are the following methods; • Crushed – a method of pressing are using intense pressure in means of destroying its original form • Melted – a method use of having to change a particular substance’s formation or appearance from having it to be solid to liquid • Moved or eroded – a way of having to wear out its natural agents in means of destroying it

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An ecologist studies a forest area for evidence of competition among organisms. She chooses a specific location where a tree was

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Answer:

Many tree seedlings crowd the open space and attempt to grow in the sunlight.

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3 years ago

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Personality appears to _________ as individuals age. gradually change quickly change quickly stabilize gradually stabilize

anzhelika [568]

Answer:

Gradually Change

Explanation:

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3 years ago

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One object has a charge of +5.0 · 10-6 c, and a second object has a charge of +2.0 · 10-6

ruslelena [56]

The electrostatic force between two charged objects is given by
$F=k \frac{q_1 q_2}{r^2}$
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects

In our problem:
$q_1=+5.0 \cdot 10^{-6} C$
$q_2 = +2.0 \cdot 10^{-6} C$
$r=0.5 m$
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:
$F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(5.0 \cdot 10^{-6} C)(2.0 \cdot 10^{-6}C)}{(0.5 m)^2}=0.36 N$

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4 years ago

Radio waves are waves. O longitudinal O transverse O mechanical

EleoNora [17]

Answer:

Transverse

Explanation:

Transverse wave, motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves

8 0

3 years ago

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Residential building codes typically require the use of 12-gauge copper wire (diameter 0.2053 cm) for wiring receptacles. Such c

AysviL [449]

Answer:

a) E = 4.26 W

b) E' = 6.724 W

c) copper wire is the safer option to use.

Explanation:

Given:

Diameter of the 12 gauge copper wire, d = 0.2053 cm

Thus, Radius of the 12 gauge copper wire, r = 0.2053 cm

/ 2 = 0.10265 cm = 0.10265 × 10⁻² m

Now.

the area (A) comes out as

A = π × (0.10265 × 10⁻²)²

A = 3.3103 × 10⁻⁶ m²

Length of the copper wire, L = 2.10 m

a) The resisitivity (ρ) of copper = 1.68 × 10⁻⁸ ohm m

Now,

the resistance of the copper , R = ρL/A

R = (1.68 × 10⁻⁸ × 2.1) / ( 3.3103 × 10⁻⁶)

R = 0.01065 ohm

The Energy (E) is given as,

E = I²R

where, I is the current

I = 20.0 A

on substituting the values, we get

E = 20.0² × 0.01065

E = 4.26 W

(b) For the aluminium

Resisitivity, ρ' = 2.65 × 10⁻⁸ ohm m

Now, the resistance of the aluminium wire, R' = (ρ' × L) / A

Since the cross-section of the aluminium wire is same as the copper wire

thus,

R = (2.65 × 10⁻⁸ × 2.1) / ( 3.3103 × 10⁻⁶)

R = 0.0168 ohm

Therefore,

The Rate of energy produced by the aluminium wire, E' = I²R'

E' = 20.0² × 0.0168

E' = 6.724 W

(c) From the above results, we can conclude that the power consumed or the rate of energy produced by the aluminium wire is more.

Hence, copper wire is the safer option to use.

8 0

4 years ago