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Alinara [238K]
3 years ago
6

What do waves carry through objects?

Physics
1 answer:
Jlenok [28]3 years ago
5 0
Waves carry energy through objects. mark me as brainlist.
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A test charge is placed at a distance of 2.5 × 10-2 meters from a charge of 6.4 × 10-5 coulombs. What is the electric field at t
Novosadov [1.4K]
Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance. 

E = kQ / d²

k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m

Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²

Electric field at the test charge is 921600000 N/C
8 0
3 years ago
Read 2 more answers
What is the frame of reference for a plane moving at 500 km/h?
RUDIKE [14]
The frame of reference is the rotating earth underneath the flight path of the plane, the rate of rotation of the earth is 1036 miles per hour, meaning that the pilot has to compensate this fact when landing the aircraft.
3 0
3 years ago
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A car is stopped at a red light. When the light turns green, the car starts
Darina [25.2K]

Answer:

See the explanation below

Explanation:

This happens because the coffee was at rest, at the time when the car accelerates to move forward the container containing the coffee also accelerates in the same direction, the liquid when moving suddenly spills. The same will happen if the car slows down, any sudden movement changes will cause the coffee to spill, understood by sudden movements when it accelerates or slows down.

3 0
3 years ago
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Find the ratio of the gravitational force between two planets if the masses of both planets are quadrupled but the distance betw
Snezhnost [94]

Answer:

The ratio of the new force over the original force is 16

Explanation:

Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:

F_G=G\,\frac{M_1\,\,M_2}{D^2}

So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:

F'_G=G\,\frac{4M_1\,\,4M_2}{D^2}=G\,\frac{16\,\,M_1\,\,M_2}{D^2}=16\,\,G\,\frac{M_1\,\,M_2}{D^2}= 16\,\,F_G

which is 16 times the original force.

So the ratio of the new force over the original force is 16

5 0
3 years ago
A 100 kg box sits on an incline held at rest by a very thin rope attached to another mass hanging as shown. The force of frictio
MAVERICK [17]

If friction is acting along the plane upwards

then in this case we will have

For equilibrium of 100 kg box on inclined plane we have

mgsin\theta = F_f + T

also for other side of hanging mass we have

T = Mg = 50(9.8) = 490 N

now we have

100(9.8)sin\theta = 100 + 490

980sin\theta = 590

sin\theta = 0.602

\theta = 37 degree

In other case we can assume that friction will act along the plane downwards

so now in that case we will have

mgsin\theta + F_f = T

also we have

T = Mg = 50(9.8) N

now we have

100(9.8)sin\theta + 100 = 50(9.8)

980sin\theta + 100 = 490

980 sin\theta = 490 - 100

sin\theta = 0.397

\theta = 23.45 degree

<em>So the range of angle will be 23.45 degree to 37 degree</em>

6 0
3 years ago
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