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sukhopar [10]
3 years ago
7

Technician A says that a seal can be pried out of a bore using a sharp chisel. Technician B says that smaller metal-backed seals

can often be driven into place using a standard socket. Who is correct? Group of answer choicesA. A onlyB. B onlyC. BothD. Neither
Engineering
2 answers:
attashe74 [19]3 years ago
6 0

Answer:

The correct answer is letter "C": Both.

Explanation:

Industrial seals are used at interfaces between components to prevent leakage, to maintain heat, and to avoid contamination. The design, construction, and materials they use vary depending on industrial use but the most common are Polytetrafluoroethylene (PTFE), Nitrile Buna Rubber (NBR), and fluorocarbon.

Thus, using a sharp chisel could pry a seal out of a hole and a regular socket can often be used to force smaller metal-backed seals into place. Thus, technicians "A" and "B" are correct.

FrozenT [24]3 years ago
4 0

Answer:

the correct answer is c boyh

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An office building is served by an air-cooled chiller currently operating at 115 tons (404.5 kW). The measured chilled water sup
Andrei [34K]

Answer:

B.197 gpm and 12.4 L/s

Explanation:

Given that

Load Q = 404.5 KW

Water inlet temperature= 6.1 °C

Water outlet temperature= 13.9°C

We know that specific heat for water

C_p=4.187\ \frac{KJ}{kg.K}

Now from energy balance

Q=\dot{m}C_p\Delta T

by putting the values

Q=\dot{m}C_p\Delta T

404.5=\dot{m}\times 4.187(13.9-6.1)

\dot{m}=12.38\ \frac{kg}{s}     (1 Kg/s = 15.85 gal/min)

We can say that

\dot{m}=196.31\ \frac{gal}{min}

We know that

\dot{m}=\rho\times volume\ flow\ rate

12.38=1000 x volume flow rate

volume\ flow\ rate\ = 12.38\times 10^{-3}\ \frac{m^3}{s}

So

volume flow rate = 12.38 L/s

So the option B is correct.

8 0
3 years ago
Partes de un transformador
BartSMP [9]
Está constituido por dos bobinas de material conductor, devanadas sobre un núcleo cerrado de material ferromagnético, pero aisladas entre sí eléctricamente. ... Las bobinas o devanados se denominan primario y secundario según correspondan a la entrada o salida del sistema en cuestión, respectivamente.
6 0
3 years ago
A 2 m3 rigid tank initially contains air at 100 kPa and 22 degrees C. The tank is connected to a supply line through a valve. Ai
Vaselesa [24]

Answer:

a. 9.58kgs b. 340.32KJ

Explanation:

Volume of tank= 2m³

Initial Pressure Pi= 100KPa

Initial Temperature Ti= 22 C= 295K

Line Pressure P₁= 600 KPa

Line Temperature T= 22 C= 295K

Final Pressure P2= 600 KPa

Final Temperature T2= 77 C= 350K

Use Ideal Gas Equation

PV= mRT

P₁V₁= m₁RT₁

m₁= (100 x 2)/(0.287 x 295) = 2.3622kg

P₂V₂= m₂RT₂

m₂= (600 x 2)/(0.287 x 350) = 11.946 kg

Since valve is closed and no mass leave

m₁ + mi = m₂ + me

as per above condition me= 0

mi= m₂ - m₁ = 11.946 - 2.3622 = 9.5838kg

Applying energy equation

m₁u₁ + mihi + Q = m₂u₂ + mehe + W

me and W=0

m₁u₁ + mihi + Q = m₂u₂

m₁CvT₁ + miCpTi + Q =  m₂CvT₂

Q =   m₂CvT₂- m₁CvT₁ - miCpTi

Q = (11.946 x 0.717 350) - (2.3622 x 0.717 x 295) - (9.5868 x 1.004 x 295)

Q = -340.321 KJ (Negative sign doesn't matter as energy is not a vector quantity)

4 0
3 years ago
What are the functions of money?<br> Money is money
mote1985 [20]

Answer:

Money is often defined in terms of the three functions or services that it provides. Money serves as a medium of exchange, as a store of value, and as a unit of account. Medium of exchange. Money's most important function is as a medium of exchange to facilitate transactions

Explanation:

8 0
3 years ago
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USPshnik [31]

Explanation:

Since there are no answer choices, how do we answer this? comment the answer choices below and ill edit this

8 0
3 years ago
Read 2 more answers
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