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sukhopar [10]
3 years ago
7

Technician A says that a seal can be pried out of a bore using a sharp chisel. Technician B says that smaller metal-backed seals

can often be driven into place using a standard socket. Who is correct? Group of answer choicesA. A onlyB. B onlyC. BothD. Neither
Engineering
2 answers:
attashe74 [19]3 years ago
6 0

Answer:

The correct answer is letter "C": Both.

Explanation:

Industrial seals are used at interfaces between components to prevent leakage, to maintain heat, and to avoid contamination. The design, construction, and materials they use vary depending on industrial use but the most common are Polytetrafluoroethylene (PTFE), Nitrile Buna Rubber (NBR), and fluorocarbon.

Thus, using a sharp chisel could pry a seal out of a hole and a regular socket can often be used to force smaller metal-backed seals into place. Thus, technicians "A" and "B" are correct.

FrozenT [24]3 years ago
4 0

Answer:

the correct answer is c boyh

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List five pieces of personal safety equipment which must be in everyday use in the workshop​
tatyana61 [14]

Answer:

safety glasses, hearing protection, respirator, work gloves, and work boots.

Explanation:

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3 0
3 years ago
"Vehicles begin to arrive at a parking lot at 6:00 A.M. at a rate of eight per minute. Due to an accident on the access highway,
marin [14]

Answer:

The solution and explanation is attached.

Explanation:

8 0
3 years ago
Neglecting the presence of friction, air drag, and other inefficiencies, how much gasoline is consumed when a 1300 kg automobile
koban [17]

Answer:

Explanation:

Given that, .

Mass of car is

M = 1300kg

Velocity of car

V = 80km/h = 80 × 1000/3600

V = 22.22m/s

Calculate the kinetic energy of the vehicle as follows:

K.E = ½ MV²

K.E = ½ × 1300 × 22.22²

K.E = 320,987.65 J

Given that,

Enthalpy is 45MJ / kg

h = 45MJ / kg

Then, enthalpy is given as.

Enthalpy = Energy / mass

h = E / m

45 × 10^6 = 320,987.65 / m

m = 320,987.65 / 45 × 10^6

m = 7.133 × 10^-3 kg

m = 7.133 mg

Also, given that, density is 680kg/m³

Density is given as

Density = mass / Volume

ρ = m / v

Then, v = m / ρ

v = 7.133 × 10^-3 / 680

v = 1.049 × 10^-5 m³

We know that

1mL = 10^-6 m³

Therefore,

v = 1.049 × 10^-5 m³ × 1mL / 10^-6m³

v = 10.49 mL

7 0
3 years ago
Write a program that asks the user for the name of a file. The program should display the number of words that the file contains
Flura [38]

Answer:

import java.io.*;

import java.util.Scanner;

public class CountWordsInFile {

   public static void main(String[] args) throws IOException {

       Scanner keyboard = new Scanner(System.in);

       System.out.print("Enter file name: ");

       String fileName = keyboard.next();

       File file = new File(fileName);

       try {

       

           Scanner scan = new Scanner(file);

           

           int count = 0;

           

           while(scan.hasNext()) {

               scan.next();

               count += 1;

           }

           scan.close();

           System.out.println("Number of words: "+count);        

       } catch (FileNotFoundException e) {

           System.out.println("File " + file.getName() + " not present ");

           System.exit(0);

       }

   }

}

3 0
4 years ago
Urgent!!! <br>List the assumptions that can be taken into account in torsion analysis.​
krok68 [10]

Answer:

Explanation:

In the development of a torsion formula for a circular shaft, the following assumptions are made: Material of the shaft is homogeneous throughout the length of the shaft. Shaft is straight and of uniform circular cross section over its length. Torsion is constant along the length of the shaft.

5 0
3 years ago
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