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Dafna1 [17]
3 years ago
15

The higher the hydronium ion concentration of a solution, the ______ its pH. higher or lower

Chemistry
2 answers:
andrey2020 [161]3 years ago
5 0
<h3>Answer:</h3>

The higher the hydronium ion concentration of a solution, the <u>lower</u> its pH.

<h3>Explanation:</h3>
  • The pH is the measure of acidity or alkalinity of a substance.
  • We calculate pH by using;

                  pH = -log[H+]

  • The lower the pH of a solution the more acidic it is and the higher the pH the more basic or alkaline it is.
  • pH =-log[H+] =-log[H₃O+]
  • From this relationship, the higher the hydronium ions concentration of a solution the lower the pH and the more acidic a solution is.

For example,

Solution A with a [H₃O+] of 0.003 M will have a pH of

pH = -log 0.003 M

     = 2.52

While, a solution B with a [H₃O+] of 0.025 M will have a pH of

pH = -log 0.25 M

    = 1.60

Therefore, the higher the concentration of hydronium ion of a solution the lower its pH is.

11111nata11111 [884]3 years ago
3 0

Answer:

lower

Explanation:

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HCHO2 + NaOH = NaCHO2 + H2O complete ionic
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Answer:

HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)  

Explanation:

An ionic equation uses the symbols (aq) [aqueous] to indicate molecules and ions that are soluble in water, (s) [solid] to indicate insoluble solids, and (ℓ) to indicate substances (usually water) in the liquid state.

In this reaction, aqueous sodium hydroxide reacts with aqueous formic acid to form sodium formate and water.

1. Molecular equation

HCHO₂(aq) + NaOH(aq) ⟶ NaCHO₂(aq) + H₂O(ℓ)  

2. Ionic equation

Sodium hydroxide and sodium formate are soluble ionic compounds, so we write them as hydrated ions.

HCHO₂(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + CHO₂⁻(aq) + H₂O(ℓ)  

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What evidence supports a scientist's conclusion that fossil B is older than fossil A? (4 points)
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Assuming all volume measurements are made at the same temperature and pressure, how many liters of water vapor can be produced w
maria [59]
For the reaction 2 K + F2 --> 2 KF,
consider K atomic wt. = 39
23.5 g of K = 0.603 moles, hence following the molar ratio of the balanced equation, 0.603 moles of potassium will use 0.3015 moles of F2. (number of moles, n = 0.3015)

Now, following the ideal gas equation, PV = nRT
P = 0.98 atm
V = unknown
n = 0.3015 moles
R = 82.057 cm^3 atm K^-1mole^-1 (unit of R chosen to match the units of other parameters; see the reference below)
T = 298 K
Solving for V,
V = (nRT)/P = (0.3015 mol * 82.057 cm^3 atm K^-1 mol^-1 * 298 K)/(0.98 atm)
solve it to get 7517.6 cm^3 as the volume of F2 = 7.5176 liters of F2 gas is needed.


2. Use the formula: volume1 * concentration 1 = volume 2 * concentration 2
where, volume 1 and concentration 1 are for solution 1 and volume 2 and solution 2 for solution 2.

Solution 1 = 12.3 M NaOH solution
Solution 2 = 1.2 M NaOH solution

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Aqueous concentrated nitric acid is 69% hno3 by weight and has a density of 1.42 g/ml.
OleMash [197]

Answer: -

15.55 M

35.325 molal

Explanation: -

Let the volume of the solution be 1000 mL.

Density of nitric acid = 1.42 g/ mL

Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid

= 1000 mL x 1.42 g/ mL

= 1420 g.

Percentage of HNO₃ = 69%

Amount of HNO₃ = \frac{69} {100} x 1420 g

= 979.8 g

Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol

Number of moles of HNO₃ = \frac{979.8 g}{63 g/ mol}

= 15.55 mol

Molarity is defined as number of moles per 1000 mL

We had taken 1000 mL as volume and found it to contain 15.55 moles.

Molarity of HNO₃ = 15.55 M

Mass of water = Total mass of nitric acid solution - mass of nitric acid

= 1420 - 979.8

= 440.2 g

So we see that 440.2 g of water contains 15.55 moles of HNO₃

Molality is defined as number of moles of HNO₃ present per 1000 g of water.

Molality of HNO₃ = \frac{15.55 x 1000}{440.2}

= 35.325 molal

3 0
3 years ago
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