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3 years ago

The higher the hydronium ion concentration of a solution, the ______ its pH. higher or lower

Chemistry

2 answers:

andrey2020 [161]3 years ago

5 0

<h3>Answer:</h3>

The higher the hydronium ion concentration of a solution, the <u>lower</u> its pH.

<h3>Explanation:</h3>

The pH is the measure of acidity or alkalinity of a substance.

We calculate pH by using;

pH = -log[H+]

The lower the pH of a solution the more acidic it is and the higher the pH the more basic or alkaline it is.

pH =-log[H+] =-log[H₃O+]

From this relationship, the higher the hydronium ions concentration of a solution the lower the pH and the more acidic a solution is.

For example,

Solution A with a [H₃O+] of 0.003 M will have a pH of

pH = -log 0.003 M

= 2.52

While, a solution B with a [H₃O+] of 0.025 M will have a pH of

pH = -log 0.25 M

= 1.60

Therefore, the higher the concentration of hydronium ion of a solution the lower its pH is.

11111nata11111 [884]3 years ago

3 0

Answer:

lower

Explanation:

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Net ionic equation of hydrated oxalic acid and sodium hydroxide

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3 years ago

Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o

sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is 4.50 × 10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50 × 10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

$[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4} } = 0.0106 M$

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

$\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%$

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Explanation:

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TiliK225 [7]

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Explanation:

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3 years ago

Read 2 more answers