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MariettaO [177]
4 years ago
9

A Ping-Pong ball is given an upward initial velocity. The force of air resistance causes the times of ascent and descent to be u

nequal. Which time is greater?
Physics
1 answer:
bazaltina [42]4 years ago
5 0

Answer:

Time of ascent is greater than time of descent.

Explanation:

The gravitational force always acts in the downward direction. The air drag always opposes the motion.

During ascent, the gravitational force and air drag act in opposite direction to the motion where as during descent, only air drag acts in opposite direction to the motion of the ball while gravitational force acts in the same direction. Thus, the time of ascent and descent become unequal with time of ascent being greater than time of descent.

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Select all that apply.
Sloan [31]

The first and third choices on the list will attract, because UNlike poles are facing across the gap.

Choice #1: . . . [S]-----[N] . . . [S]-----[N]

Choice #3: . . . [N]-----[S] . . . [N]-----[S]

8 0
3 years ago
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. Determine the horizontal and vertical components of reaction at the hinge A and the horizontal reaction at the smooth surface
yan [13]

Answer:

Please find attached file for complete answer solution and explanation of same question.

Explanation:

6 0
4 years ago
What is the relationship between a wave's energy and its effect on matter?
Nina [5.8K]

Answer:

The wave function for a material particle is often called a matter wave. The relationship between momentum and wavelength for matter waves is given by p = h/λ, and the relationship energy and frequency is E = hf.

Explanation:

5 0
3 years ago
Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te
solong [7]

To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

The intrinsic carrier concentration is the number of electrons in the conduction band or the number of holes in the valence band in intrinsic material. This number of carriers depends on the band gap of the material and on the temperature of the material.

In general, this can be written mathematically as

\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}

Both are identical semiconductor but the difference is band gap which is:

E_{g1} = 1.1eV

n_{i1} = 1*10^{19}m^{-3}

E_{g2} = 1.2eV

T=300K

The ratio between the two phases are given as:

\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}

\frac{\eta_{i1}}{\eta_{i2}} = e^{\frac{E_{g2}-E_{g1}}{2KT}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{-1.932367}

\frac{\eta_{i1}}{\eta_{i2}} =0.145

Therefore the ratio of intrinsic carrier densities for the two materials at room temperature is 0.145

7 0
4 years ago
Earthquakes at fault lines in Earth's crust create seismic waves, which are longitudinal (P-waves) or transverse (S-waves). The
chubhunter [2.5K]

Answer:

B=2.025\times 10^{11}\ Pa

Explanation:

It is given that,

Speed of P- waves, v = 9 km/s = 9000 m/s

The density of rock is about 2500\ kg/m^3

We need to find the average bulk modulus of Earth's crust. Let it is given by B. So,

v=\sqrt{\dfrac{B}{d}} \\\\B=v^2d\\\\B=(9000)^2\times 2500\\\\B=2.025\times 10^{11}\ Pa

So, the bulk modulus of the Earth's crust is 2.025\times 10^{11}\ Pa.

8 0
4 years ago
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