Moles of Zn present= 2.36/65.4= 0.0361 moles
Therefore maximum moles of ZnO= 0.0722
Mass of one mole of ZnO= 81.4
Mass of ZnO produced= 0.0722 x 81.4= 5.87g
Answer:- 21.4 grams of
are formed.
Solution:- The balanced equation is:

From this equation, lithium and nitrogen reacts in 6:1 mol ratio. Limiting reactant gives the theoretical yield of the product. We will calculate the grams of the product for the given grams of both the reactants and see which one of them gives the limited amount of the product. This limited amount of the product will be the theoretical yield.
The molar mass of Li is 6.94 gram per mol and for
It is 28.02 gram per mol. The molar mass of
is 34.83 gram per mol. The calculations for the grams of the product for given grams of both the reactants are shown below:

= 

= 
From above calculations, Li gives least amount of the product. So, 21.4 g of
are formed.
Electrons: negative
Protons: positive
Neutrons: nuetral
We have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula:
Kc = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 = 0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07