The length of the room is 96 ft.
Let L be the length of the room and W be the width of the room.
Since the length is twice its width, L = 2W.
Its area A = LW
= 2W × W
= 2W²
If each side were increased by 1 foot, then its new area is A' = (L + 1)(W + 1)
= (2W + 1)(W + 1)
= 2W² + 3W + 1
Since the room would contain 145 ft more if each side were increased by 1 foot, then its new area is A' = A + 145 = 2W² + 3W + 1
2W² + 145 = 2W² + 3W + 1
145 = 3W + 1
3W = 145 - 1
3W = 144
W = 144/3
W = 48 ft.
Since its length L = 2W, substituting W = 48 into the equation, we have
L = 2(48)
L = 96 ft
So, the length of the room is 96 ft.
Learn more about length of a room here:
brainly.com/question/24375989
Answer:
The height jumped by the sprinter is 5.10 meters.
Explanation:
It is given that,
Speed of the sprinter, v = 10 m/s
We need to find the height jumped by the sprinter his or her kinetic energy gets converted into upward motion. It can be calculated using conservation of energy as :


g is the acceleration due to gravity

h = 5.10 meters
So, the height jumped by the sprinter is 5.10 meters. Hence, this is the required solution.
Answer:
Your father is still your real father since the mother and the brother never married, and that does not make your brothers cousins
Explanation:
Answer:
500 m/s
Explanation:
Momentum, p is a product of mass and velocity. From law of conservation of momentum, the initial momentum equals final momentum

Here m and v represent mass and velocity respectively and subscripts 1 and 2 represent car and barrier respectively
Therefore, the velocity of barrier will be 500 m/s
Answer:
7.5
Explanation:
The dielectric constant of ceramics is about 7.5.
The dielectric constant of a substance is the ratio of the electric permeability of a substance to the electric permeability of free space.
Dielectric constant gives a good overview about the ability of substance to store charges compared to another.
Most substances have their electric constant and they suggest the ease by which they can store electrical energy. This is very important in developing capacitors.