Answer:
(a) 3.807 s
(b) 145.581 m
Explanation:
Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.
The distance traveled by car after Δt (seconds) at 
speed is
The distance traveled by the motorcycle after Δt (seconds) at 
speed and acceleration of a = 8 m/s2 is
We know that the motorcycle catches up to the car after Δt, so it must have covered the distance that the car travels, plus their initial distance:
(b)
Answer:
a) Initial Value Problem
dv/dt = 4 - 0.1v
v(0) = 0
b) solution to the IVP
v(t) = 40(1 - e^(-t/10))
c) Limiting velocity
Vo = 40 ft/s
Position of the car after 12 hours
X = 14,390 ft
Explanations:
The complete explanations of each of the sections contained in the question are in the files attached to this solution.
The initial velocity of the train is 12.56 m/s.
<h3>
Initial velocity</h3>
The initial velocity of the train can be determined by using the first kinematic equation as shown below;
v = u + at
u = v - at
where;
- v is the final velocity = 110 km/h = 30.56 m/s
- u is the initial velocity
u = 30.56 - (36 x 0.5)
u = 12.56 m/s
Thus, the initial velocity of the train is 12.56 m/s.
Learn more about initial velocity here: brainly.com/question/19365526
29 million are type 2, that would be about 9.5 percent. :)
Answer: option c: It orbits beyond the Earth's atmosphere to avoid scattering of light.
Explanation:
Hubble space telescope orbits Earth and sends images of distant objects. The images formed by Hubble are better than the optical telescopes used on land. This is because the Hubble telescope is a space telescope. Light from the distant objects when reaches the land telescopes transmits through atmosphere, where scattering occurs. Some the light rays bounce back. This is avoided by the space telescope Hubble.
