Question

In a reaction at equilibrium, the partial pressure of SO2 is 137 torr and that of CL2 is 285 torr. What is the partial pressure of SO2Cl2 in this mixture?

Answer 1

Answer:

422 torr

Explanation:

According to Dalton's law of partial pressure, the total pressure exerted by a mixture of gases is the sum of their individual/partial pressure. Mathematically, this can be expressed as:

$P_{total} = P_{1} + P_{2} + ........+ P_{n}$

In this case, $P_{SO2}$ = 137 torr, $P_{Cl2}$ = 285 torr, hence

$P_{SO2Cl2}$ = $P_{SO2} + P_{Cl2}$

                   = 137 + 285

                        = 422 torr

The partial pressure of SO2Cl2 in this mixture is 422 torr.