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solniwko [45]
3 years ago
9

A 4 feet tall student went for swimming in a pool.He saw the depth of the water in the pool less than 4 feet.Will he be drowned?

Write with reason.
Those who give me correct ans I will start to follow him /her​
Physics
2 answers:
Serjik [45]3 years ago
8 0

Answer:

No, he won't be drowned.

Explanation:

We have given,

The height of the student = 4 feet,

Depth of the pool( in feet ) = x ( say ) < 4 feet,

Since, the depth of the pool < height of the student,

Thus, if the student went for swimming in a pool, however he does not know swimming, he will not be drowned until he is suffering from an injury or external force.

Julli [10]3 years ago
7 0

Answer:

No, he will not be drowned.

Explanation:

The student will only be drowned if:

                          Height of student < Depth of pool  

But in the current scenario reverse is true. So,

                           Height of student > Depth of pool

Hence, student will not be drowned even if he does not know swimming. He can only be drowned if some external force tries to do so or suffering from an injury.

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Calculate the pressure exerted on the floor when an elephant who weighs 6000 N stands on one foot which has an area of 20 m2
kondor19780726 [428]

Answer:

300 Pascal

Explanation:

Given

weight or force (F) = 6000 N

area (A) = 20 m²

pressure (p) = ?

we know

the force acting normally per unit area is pressure. So

P = F / A

= 6000 / 20

= 300 Pascal

Hope it will help :)

3 0
3 years ago
A 86g ball is dropped vertically to the floor from a height of 2.87m and bounces to a height of 1.28. What is the magnitude of t
irga5000 [103]

Answer:

The impulse received by the ball from the floor during the bounce is approximately 1.11329438 m·kg/s

Explanation:

The given mass of the ball, m = 86 g = 0.089 kg

The height from which the ball is dropped, H = 2.87 m

The height to which the ball bounces, h = 1.28 m

Mathematically, we have;

Δp = F·Δt

Where;

Δp = The change in momentum = m·Δv

F = The applied force

Δt = The time of contact with the force

The velocity of the ball just before it touches the ground, v₁ = -√(2·g·H)

The velocity with which the ball leaves, v₂ = √(2·g·h)

The change in momentum, Δp = m·(v₂ - v₁)

∴ Δp = m·(√(2·g·h) - (-√(2·g·H))) = m·(√(2·g·h) +√(2·g·H) )

The impulse, Δp, received by the ball from the floor during the bounce is given as follows;

Δp = 0.089 kg × (√(2 × 9.8 m/s² × 1.28 m) + √(2 × 9.8 m/s² × 2.87 m)) ≈ 1.11329438 m·kg/s

The impulse received by the ball from the floor during the bounce, Δp ≈ 1.11329438 m·kg/s

6 0
3 years ago
Two vectors of magnitudes 30 units and 70 units are added to each other. What are possible results of this addition? (section 3.
Yanka [14]

Answer:

the correct answer is option C which is 50 units.

Explanation:

given,

two vector of magnitude = 30 units and of 70 units

to calculate resultants vector = \sqrt{a^2+b^2+2 a b cos\theta}

cos θ value varies from -1 to 1

so, resultant vector

=\sqrt{a^2+b^2-2 a b cos\theta}\ to\ \sqrt{a^2+b^2+ 2 a b cos\theta}

a = 30 units    and  b = 70 units

= \sqrt{30^2+70^2-2\times 30\times 70}\ to\ \sqrt{30^2+70^2+2\times 30\times 70}

=   40 units to 100 units

hence, the correct answer is option C which is 50 units.

                       

4 0
3 years ago
How much force is needed to stop a body of mass 10kg​
almond37 [142]

Answer:

Force of <u>1</u><u>0</u><u>0</u><u> </u><u>N</u><u> </u>will be needed.

Explanation:

Force, F = m \times g

g is acceleration due to gravity

m is the mass

F = (10 \times 10) \\ F =  100 \: newtons

3 0
2 years ago
Read 2 more answers
Which statement accurately describes impulse?<br> State corrrect answer from the choices
zhuklara [117]

Answer:

5354..

Explanation:

6 0
2 years ago
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