The AREA of the shaded region is the moving object's displacement.
Correct question:
Consider the motion of a 4.00-kg particle that moves with potential energy given by

a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?
b) What is the magnitude of the force on the 4.00-kg particle when it is located at x = 5.00 m?
Answer:
a) 3.33 m/s
b) 0.016 N
Explanation:
a) given:
V = 3.00 m/s
x1 = 1.00 m
x = 5.00

At x = 1.00 m

= 4J
Kinetic energy = (1/2)mv²

= 18J
Total energy will be =
4J + 18J = 22J
At x = 5

= -0.24J
Kinetic energy =

= 2Vf²
Total energy =
2Vf² - 0.024
Using conservation of energy,
Initial total energy = final total energy
22 = 2Vf² - 0.24
Vf² = (22+0.24) / 2

= 3.33 m/s
b) magnitude of force when x = 5.0m



At x = 5.0 m


= 0.016N
Answer:

Explanation:
A polarizer changes the orientation of the oscillations of a light wave.
I₀ = Intensity of unpolarized light = 10
θ = Angle given to the polarizer = 60°
Intensity of light
I = I₀cos²θ
⇒I = 10cos²60

So, the after passing through the second polarizer is 
Answer:
Push the washing machine harder onto the surface it sits upon, increasing friction between the two.
Explanation:
Answer
newtons first law says that when an equal force is applied to force it causes it to accelerate
Explanation: