The range of the projectile is 188 m
Explanation:
The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
The path of a projectile is the combination of these two motions: see figure in attachment.
In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.
We have:
t = 5.0 s (time of fligth of the projectile)
and the horizontal velocity is constant, and it is given by
where
is the initial velocity
is the angle of projection
Substituting,
And therefore, the range of the projectile is:
Learn more about projectile motion:
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Answer:
34.5 m
Explanation:
Given data : An elephant produces 10 Hz sound wave. Assuming the speed of sound in air is 345 m/s. To find : What is the wavelength of sound ? Answer : The wavelength of the sound is 34.5 m.
<span>fluid friction of the air also known as drag</span>
Answer:
t = 16.94 s
Explanation:
t is the time passes before police catch the speeder
speed of speeder Vo = V = 23.3 m/s
T = t
Police Info
Vo = 0 m/s
a = 2.75 m/s^2
t = t
Now,
displacement of the police car = displacement of the speeder.
x_{police} = Vo *t + 1/2 at^2
since Vo = 0
x police = 1/2 at^2
x police = 1/2 (2.75)(t)^2
Now the displacement of speeder is
x_{speeder} = Vt
x_{speeder} = 23.3 t
x_{speeder} = x_{police}
23.3 t = 1/2 * 2.75 t^2
23.3 t = 1.375 t^2
t = 23.3\1.375
t = 16.94
t = 16.94 s
Electric potential energy, or Electrostatic potential energy, is a potential energy that results from conservative Coulomb forces and is associated with the configuration of a particular set of point charges within a defined system.
