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Mnenie [13.5K]
3 years ago
5

Predict where on this graph you would find the GREATEST concentration of atomic mass based on what you know regarding the locati

on of mass density relative to the center of the atom. A) A B) B C) C D) D
Chemistry
1 answer:
anastassius [24]3 years ago
4 0

Answer:

The Answer is A

Explanation:

i just did this on usa test prep

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AICI3(s)+Ca 3N2(s)-AIN(S)+CaCl2(s)
disa [49]

Answer:

2AlCl3 + Ca3N2 - 2AlN+ 3CaCl2

8 0
3 years ago
What would be the mass in grams of 1.204 x 1024 molecules of sulfur dioxide
melomori [17]

Answer:

mass of sulfur = 96 g

Explanation:

no of moles of sulfur dioxide in 1.204\times 10^{24} molecules = \frac{1.204\times 10^{24}}{avagadro number }= \frac{1.204\times 10^{24}}{6.023\times 10^{23}}

                                       = 2 moles

therefore mass of sulfur dioxide = moles×atomic number

                                                      =2×(16+32)

                                                      =96

6 0
3 years ago
The precision of a measuring instrument is based on the fineness of its scale subdivisions.
Liono4ka [1.6K]
The answer is True . The precision of a measuring is based on the fitness of its scale subdivisions
3 0
4 years ago
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Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whet
Sloan [31]

The given reaction is as follows:

2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ

It is known that dSsurr = -dHsys / T (Temp = 355 K)

So,  dSsurr = - (-114 × 1000) / 355

dSsurr = +321.12 J/K

Hence, the value of dSsurr is +321.12 J/K

For a reaction to be spontaneous, dG<0,

Also dStotal = dSsys + dSsurr > 0

It is known that dG = dHsys - TdSsys,

Now let us assume,

dG<0

Also, dStotal = dSsys + dSsurr > 0

(-114 × 1000) - (355 × dSsys) <0

355 × dSsys > -114 × 1000

dSsys > -321

dSsys >dSsurr

dSsys + dSsurr > 0

dStotal > 0

Thus, the assumption is correct, and the given reaction is spontaneous. Hence, the final answer is Ssurr = +321 J/K reaction is spontaneous.



8 0
3 years ago
What mass of NH4NO3 would you need to make 250.0mL of a 0.78M solution?
katrin [286]

Answer:

a

Explanation:

8 0
3 years ago
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