Answer:
<621, 0 , 0>
Explanation:
given,
mass of the car ,m = 1425 Kg
location of car = < 266, 0, 0 > m
momentum of the car = < 46000, 0, 0 > kg.m/s
M v_x = 46000
1425 x v_x = 46000
v_x = 32.28 m/s
v_y = 0 m/s
v_z = 0 m/s
Location of the car after 11 s
x = v_x t + 266
x = 32.28 x 11 + 266
x = 621 m
hence, the location of car after 11 s is equal to <621, 0 , 0>
Answer:
5.61s
Explanation:
And we need to find out the time taken by the ball to reach the ground .
- The initial velocity of the ball will be 0 since it is dropped .
Here we can use the First equation of motion , namely ;
where the symbols have their usual meaning . Now substituting the respective values , we have,
Answer:
The first situation is impossible.
Explanation:
"An object has constant non-zero velocity and changing acceleration."
Not possible, acceleration is the change of velocity. For velocity to remain constant the acceleration must remain zero. If acceleration is changing it might be zero at some point, but will not remain zero, so the velocity will change.
"An object has zero velocity but non-zero acceleration."
An object might have a velocity of zero at some point while under an acceleration. An example of this is an object that is thrown upwards. At the top of the trajectory it will have a velocity of zero but will be under the acceleration of gravity.
"An object has constant non-zero acceleration and changing velocity."
This is what any object in free fall do.
"An object has velocity directed east and acceleration directed east."
No problem with that.
"An object has velocity directed east and acceleration directed west."
No problem with that, it will reduce its velocity.
Answer:
a) p = 95.66 cm, b) p = 93.13 cm
Explanation:
For this problem we use the constructor equation
where f is the focal length, p and q are the distances to the object and the image, respectively
the power of the lens is
P = 1 / f
f = 1 / P
f = 1 / 2.25
f = 0.4444 m
the distance to the object is
the distance to the image is
q = 85 -2
q = 83 cm
we must have all the magnitudes in the same units
f = 0.4444 m = 44.44 cm
we calculate
1 / p = 0.010454
p = 95.66 cm
b) if they were contact lenses
q = 85 cm
1 / p = 0.107375
p = 93.13 cm
C)Visible Light-the hint:Visible light.