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mixer [17]
3 years ago
5

A. The structure of [NO3]- is either trigonal planar or trigonal pyramidal draw both possible structures and determine the point

group for each using drawing software. B. Which irreducible representations represent the translational and rotational modes for each possible structure of [NO3]-?

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
6 0

Answer:

Look at the picture.

Explanation:

For planar anion point group is D3h. For trigonal piramidal point group is C3v.

On picture 2 and 3 are the tables for each point group. Irreducible representations its the horizontal rows in tables. Where you see x, y and z it's translation of p-orbitals. Where you see R - it's rotations.

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A 135-g sample of a metal requires 2.50kj to change its temperature from 19.5 degrees Celsius to 100.0 degrees Celsius. What is
PolarNik [594]
Q = m x c x ΔT

2500 = 0.135 x C x 80.5

2500 = 10.8765 x C

C = 230.043 J/Kg.K

hope this helps
7 0
3 years ago
Read 2 more answers
4.564000 x 10^-4 express how many significant figures
Vaselesa [24]

Answer: 7

Explanation:

Before a number but after a decimal. The zeros at the end would usually mean that it doesn't count but since the numbers are before the zeros and after a decimal it's 7 sig figs

5 0
3 years ago
What type of reaction is shown below? <br>a) Addition reaction <br>b) Esterification​
Gemiola [76]

Answer:

a) Addition reaction, is your answer

6 0
3 years ago
2NO + 3MnO2 + 4H â 2NO3- + 3Mn2 + 2H2O For the above redox reaction, assign oxidation numbers and use them to identify the eleme
mixer [17]

Answer:

Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).

Explanation:

Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^{2+} + 2H_2O

Next, we assign the oxidation numbers as follows:

2N^{2+}O^{2-} + 3Mn^{4+}O^{-2}_2 + 4H^+ \rightarrow 2(N^{5+}O^{2-}_3)^- + 3Mn^{2+} + 2H^+_2O^{2-}

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

Regards!

4 0
2 years ago
1. 750 x 10^3 ng to g​
Temka [501]

Answer:

1.750×10^-6 g

Explanation:

we know n is 10^-9. all you have to do is to replace n with 10^-9.

so the answer is

1.750×10^3×10^-9 g

which is equal to 1.750×10^-6 g

if anything is unclear, ask freely.

4 0
3 years ago
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