ompare your TLC analysis with the results of the column chromatography. More polar molecules move more slowly through silica tha
n less polar molecules. Describe why silica gel chromatography is a good method of separating methyl orange from biphenyl. Based on the structure of Biphenyl and Methyl Orange, predict which compound will have a higher Rvalue on TLC and explain your choice.
1 answer:
Biphenyl will have a higher R value than the Methyl Orange.
Explanation:
Biphenyl is a aromatic hydrocarbon and it is a nonpolar molecule.
Methyl Orange is a organic compound with a -SO₃⁻Na⁺ polar functional group which will induce a high polarity in the compound.
You may find the chemical structures of both molecules in the attached picture.
Column chromatography, which use as stationary phase silica gel, is a good technique for separation of the Methyl Orange from Biphenyl.
Being a non-polar molecule, Biphenyl will have a higher R value than the Methyl Orange.
To separate them you use a appropriate solvent as eluent, as exemple chloroform, and Biphenyl will elute first from the column and after that, as a separate phase, Methyl Orange will elute thus separating them.
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Answer:
(a) The rate of disappearance of is:
M/s
(b) The value of rate constant is: 0.83036
(c) The units of rate constant is:
(d) The rate will increase by a factor of 3.24
Explanation:
The rate of a reaction can be expressed in terms of the concentrations of the reactants and products in accordance with the balanced equation.
For the given reaction:
rate = =
=
-----(1)
According to the question, the reaction is second order in NO and first order in .
Then we can say that, rate = k -----(2)
where k is the rate constant.
The rate of disappearance of NO is given:
=
M/s.
(a) From (1), we can get the rate of disappearance of .
Rate of disappearance of =
= (0.5)*(
) M/s =
M/s.
(b) The rate of the reaction can be obtained from (1).
rate = = (0.5)*(
)
rate = M/s
The value of rate constant can be obtained by using (2).
rate constant = k =
k = = 0.83036
(c) The units of the rate constant can be obtained from (2).
k =
Substituting the units of rate as M/s and concentrations as M, we get:
=
(d) The reaction is second order in NO. Rate is proportional to square of the concentration of NO.
If the concentration of NO increases by a factor of 1.8, the rate will increase by a factor of = 3.24