Biphenyl will have a higher R value than the Methyl Orange.
Explanation:
Biphenyl is a aromatic hydrocarbon and it is a nonpolar molecule.
Methyl Orange is a organic compound with a -SO₃⁻Na⁺ polar functional group which will induce a high polarity in the compound.
You may find the chemical structures of both molecules in the attached picture.
Column chromatography, which use as stationary phase silica gel, is a good technique for separation of the Methyl Orange from Biphenyl.
Being a non-polar molecule, Biphenyl will have a higher R value than the Methyl Orange.
To separate them you use a appropriate solvent as eluent, as exemple chloroform, and Biphenyl will elute first from the column and after that, as a separate phase, Methyl Orange will elute thus separating them.
Learn more about:
chromatography
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Answer: The molar concentration of oxygen gas in water is .
Explanation:
Partial pressure of the gas = 685 torr = 0.8905 bar
1 torr = 0.0013 bar
According Henry's law:
Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar
Let the number of moles of gas in 1 liter water be n.
1 Liter water = 1000 g of water
Moles of water in 1 L
Molar concentration of oxygen gas in 1 L of water:
The molar concentration of oxygen gas in water is .
Here we have to get the of the reaction at 520 K temperature.
The of the reaction is 1.705 atm
We know the relation between and
is
, where
= The equilibrium constant of the reaction in terms of partial pressure,
= The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.
Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅
Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole
The given value of is 4.0×10⁻²
The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.
On plugging the values in the equation we get,
Or, = 1.705 atm
Thus, the of the reaction is 1.705 atm