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scZoUnD [109]
3 years ago
9

An object is thrown with an initial speed v near the surface of Earth. Assume that air resistance is negligible and the gravitat

ional field is constant. An object is thrown with an initial speed u near the surface of Earth. Assume that air resistance is negligible and the gravitational field is constant. If the object is thrown horizontally, the direction and magnitude of its acceleration while it is in the air is _________.a. upward and decreasing b. upward and constant c. downward and decreasing d. downward and increasing e. downward and constant

Physics
2 answers:
IgorLugansk [536]3 years ago
3 0

Answer:

E. downward and constant

Explanation:

Freefall is a special case of motion with constant acceleration because the acceleration due to gravity is always constant and downward. This is true even when an object is thrown upward or has zero velocity.

For example, when a ball is thrown up in the air, the ball's velocity is initially upward. Since gravity pulls the object toward the earth with a constant acceleration ggg, the magnitude of velocity decreases as the ball approaches maximum height. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth.

UNO [17]3 years ago
3 0

Answer:

E. downward and constant

Explanation:

An object in free fall experiences constant acceleration if air resistance is negligible.

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A system consists of N particles that can occupy two energy levels: a nondegenerate ground state and a three-fold degenerate exc
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Answer:

Ng = 0.893 N,  Ne = 0.107N

Explanation:

Number of particles in Ground state = Ng

Number of particles in Excited state = Ne

Ne/Ng = e^{(-ΔE)/kt}

Since excited state is 3 fold degenerate

Ne/Ng =3 x e^{(-ΔE)/kt}

ΔE = Energy difference between ground and excited states = 0.25eV

T = 960 K

Constant k = 8.617 x 10^-5 eV/K

Ne/Ng = 3 x e^{-0.25/(8.617x10^-5) x 960}

           = 3 x e^(-3.188645)

           = 3 x 0.0412 = 0.1237 ≅ 0.12

Ne = 0.12 Ng

but Ne + Ng = N, where is N is total number of particles, substituting Ne into equation we get,

Ng(1 + 0.12) = N

Ng = N/1.12 = 0.893N

and Ne = 0.12 x 0.893 N = 0.107 N

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