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Marina CMI [18]
3 years ago
7

A particle moving in the x direction is being acted upon by a net force f(x)=cx2, for some constant

Physics
1 answer:
makkiz [27]3 years ago
6 0
The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
\Delta K = W
The work done on the particle is the integral of the force on dx:
W= \int\limits^{3L}_L {F(x)} \, dx = \int\limits^{3L}_L {cx^2} \, dx = \frac{26}{3}cL^3
So, this corresponds to the change in kinetic energy of the particle.
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If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
AveGali [126]

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Explanation:

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q= 4.3× 10^-18 C

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hjlf
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Likurg_2 [28]

Answer:

4 seconds

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