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2 years ago

A particle moving in the x direction is being acted upon by a net force f(x)=cx2, for some constant

1 answer:

6 0

The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
$\Delta K = W$
The work done on the particle is the integral of the force on dx:
$W= \int\limits^{3L}_L {F(x)} \, dx = \int\limits^{3L}_L {cx^2} \, dx = \frac{26}{3}cL^3$
So, this corresponds to the change in kinetic energy of the particle.

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Batteries can supply a steady flow of electrons.<br> True<br> False

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The answer is TRUE, batteries CAN supply a steady flow of electrons.

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The energy stored in a wooden log transforms when the log is burned. Which of the following explanations BEST describes how the

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Answer:

D. the amount of chemical energy equals the amount of heat and light energy.

Explanation:

Given that the first law of thermodynamics affirmed that energy is neither created nor destroyed however, it can be transformed from one form to another. In other words, while, during the transformation of energy, no energy is lost, the input energy is also equal to output energy.

Hence, the chemical energy stored in the log is EQUAL to the heat and light energy produced by burning.

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(pleases show work)

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a. 46 m/s east

The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:

$v=u+at$

where

v is the velocity calculated at time t

u is the initial velocity

a is the acceleration

The jet in the problem has, taking east as positive direction:

u = +16 m/s is the initial velocity

$a=+3 m/s^2$ is the acceleration

Substituting t = 10 s, we find the final velocity of the jet:

$v=16 + (3)(10)=46 m/s$

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b. 310 m

The displacement of the jet can be found using another suvat equation

$s=ut+\frac{1}{2}at^2$

where

s is the displacement

u is the initial velocity

a is the acceleration

t is the time

For the jet in this problem,

u = +16 m/s is the initial velocity

$a=+3 m/s^2$ is the acceleration

t = 10 s is the time

Substituting into the equation,

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