Answer:
The current flowing through the wire is 9 A.
Explanation:
Given;
quantity of charge passing through the wire, Q = 36 C
duration of the charge flow, t = 4 s
The current flowing through the wire is calculated as;
Q = It
I = Q / t
where;
I is the current flowing in the wire
I = 36/4
I = 9 A
Therefore, the current flowing through the wire is 9 A.
Answer:
Kinetic Energy
Explanation:
Kinetic energy is energy due to motion.
Answer:
114.26
Explanation:
a)Formula for per unit impedance for change of base is
Zpu2= Zpu1×(kV1/kV2)²×(kVA2/kVA1)
Zpu2: New per unit impedance
Zpu1: given per unit impedance
kV1: give base voltage
kV2: New bas votlage
kVA1: given bas power
kVA2: new base power
In the question
Zpu2=??
Zpu1= 0.3
kV2=24kV
kV1= 13.8 kV
kVA2= 1MVA ×1000= 1000 kVA
kVA1=500kVA
Zpu2= 0.3(13.8/24)²×(1000/500)
Zpu2= 0.198
b) to find ohmic impedance we will first calculate base value of impedance(Zbase). So,
Zbase= kV²/MVA
Zbase= 13.8²/(500/1000)
Zbase=380.88
Now that we have base value of impedance, Zbase, we can calculate actual ohmic value of impedance(Zactual) by using the following formula:
Zpu=Zactual/Zbase
0.3= Zactual/380.88
Zactual= 114.26 ohms
That marking means that when the expected voltage is connected
between the two contacts of the bulb, it will dissipate 100 joules of
energy every second, in the form of heat and light.