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IrinaK [193]
3 years ago
9

according to one acid base theory the forward reaction is classified as an acid base reaction because

Chemistry
1 answer:
pav-90 [236]3 years ago
8 0
According to one acid base theory the forward reaction is classified as an acid base reaction because H2S is a H donor and CH3NH2 is a H acceptor. 
According to the acid base theory; an acid is the proton donor or hydrogen ions donor while the base is the proton acceptor or hydrogen ion acceptor. 
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Energy released from atomic reactions is called?
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The answer is nuclear energy
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Chuck has a very detailed model of the solar system where each planet is made out of granite rock. Since his little sister reall
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So there is a change in mass which for the purpose of this question should be  quite different. His sister's ought to be much lighter than his. He would find it easier to pick up.

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What determines an object’s ability to float?
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3 0
2 years ago
If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form
Mumz [18]

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0
2 years ago
What is the PH of a 1.3×(10)^-9 M HBr solution?
olga nikolaevna [1]

pH solution = 8.89

<h3>Further explanation</h3>

Given

The concentration of HBr solution = 1.3 x 10⁻⁹ M

Required

the pH

Solution

HBr = strong acid

General formula for strong acid :

[H⁺]= a . M

a = amount of H⁺

M = molarity of solution

HBr⇒H⁺ + Br⁻⇒ amount of H⁺ = 1 so a=1

Input the value :

[H⁺] = 1 x  1.3 x 10⁻⁹

[H⁺] = 1.3 x 10⁻⁹

pH = - log [H⁺]

pH = 9 - log 1.3

pH = 8.89

7 0
2 years ago
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