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Svetlanka [38]
3 years ago
14

The following are the weights,in pounds, of some dogs at a kennel: 36,45,29,39,51,49.

Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

Median = 42  pounds

Step-by-step explanation:

It is given that the following are the weights,in pounds, of some dogs at a kennel: 36,45,29,39,51,49.

Arrange the data in ascending order.

29, 36, 39, 45, 49, 51

Total number of terms = 6 (even)

So, the formula for median is

Median=\dfrac{\frac{n}{2}\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}

Median=\dfrac{\frac{6}{2}\text{th term}+(\frac{6}{2}+1)\text{th term}}{2}

Median=\dfrac{3\text{rd term}+4\text{th term}}{2}

Median=\dfrac{39+45}{2}

Median=42

Hence, the median weight is 42 pounds.

To find the median, units of the data should be same. If one of the weights were given in kilograms, then we cannot find median.

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A lab technician made a 14 cm diameter hole through the middle of a cylinder that has a diameter of 20 cm and a height of 28 cm.
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Answer:

The volume of the finished cylinder is 4486.2 m^3

Step-by-step explanation:

To find the volume of the finished cylinder, we have to first find the volume of the hole (with 14 cm diameter and a height of 28 cm) and subtract it from the volume of the original cylinder (with diameter of 20 cm and a height of 28 cm).

Note: The hole is also cylindrical in shape.

The volume of a cylinder is given as:

V = \pi r^2h

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VOLUME OF THE HOLE

The diameter of the hole is 14 cm, hence, its radius is 7 cm (14 / 2 = 7)

Its volume is:

V = \pi *7^2 * 28\\V = 4310.3 m^3

VOLUME OF THE ORIGINAL CYLINDER

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Its volume is:

V = \pi *10^2 * 28\\V = 8796.5 m^3

Hence, the volume of the finished cylinder will be:

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