A baseball is thrown by the center fielder (from shoulder level) to home plate where it is caught (on the fly at eye level) by t
he catcher. At what point does the magnitude of the vertical component of velocity have its maximum value? (air resistance is negligible)
1 answer:
At the highest point of the trajectory the vertical component will have its zero velocity, and the descent caused by the force of gravity will begin.
Since the ball is thrown with a certain speed, the vertical component reaches its highest point (upwards), until returning to the receiver who will receive the ball with the same vertical component but in the opposite direction (downwards).
Therefore the vertical component will have its highest value at launch.
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Answer:
v = 6.3 m/s
Explanation:
- Since no significant air resistance exists, total mechanical energy must be kept constant at any time.
- At the top of the cliff, all the energy is gravitational potential energy, as follows:
- If we choose the ground level as our zero reference level for the gravitational potential energy, Ui is simply:
- Ui = m*g*h (1)
- At any height, the sum of the kinetic and the gravitational potential energy must be equal to (1).
- We know from the question, that at the point of interest, both types of energies must be equal each other, so we can write the following expression from (1):
- Dividing both sides by m, simplifying, and solving for v, we get:
- v = 6.3 m/s (with two significative figures)
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