a.) Asp and Lys
Asp will elute first from the column because it has less positively charged functional groups than Lys.
b.) Arg and Met
Met will elute first from the column because it has less positively charged functional groups than Lys.
c.) Glu and Val
Glu will elute first from the column because it has more negativity functional groups than Lys and will be not be much retained by the -SO₃⁻ groups from the ion-exchange coloumn.
d.) Gly and Val
Gly will elute first from the column because Lys have a longer alkyl chain which will be attracted by the strongly hydrophobic backbone for the resin.
e.) Ser and Ala
Ser will be eluted first from the column because Ala alkyl chain will be more attracted by the strongly hydrophobic backbone for the resin. Ser have an -OH group which will decrease the hydrophobicity of the alkyl chain and will not be so much retained on the column.
Answer:
see explanation
Explanation:
The process of ionization to produce cations is endothermic. For formation of Ca⁺² two ionization steps need be illustrated as follows...
1st ionization step: Ca° + 590Kj => Ca⁺ + e⁻
2nd ionization step: Ca⁺ + 1151Kj => Ca⁺² + e⁻
__________________________________-
Net Ionization Rxn: Ca° + 1741Kj => Ca⁺² + 2e⁻
They achieve stable structures by sharing their single, unpaired electron.
Answer:
ΔG°rxn = +50.8 kJ/mol
Explanation:
It is possible to obtain ΔG°rxn of a reaction at certain temperature from ΔH°rxn and S°rxn, thus:
<em>ΔG°rxn = ΔH°rxn - T×S°rxn (1)</em>
In the reaction:
2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l)
ΔH°rxn = 3×ΔHfNO2 + ΔHfH2O - (2×ΔHfHNO3 + ΔHfNO)
ΔH°rxn = 3×33.2kJ/mol + (-285.8kJ/mol) - (2×-207.0kJ/mol + 91.3kJ/mol)}
ΔH°rxn = 136.5kJ/mol
And S°:
S°rxn = 3×S°NO2 + S°H2O - (2×S°HNO3 + S°NO)
ΔH°rxn = 3×0.2401kJ/molK + (0.0700kJ/molK) - (2×0.146kJ/molK + 0.2108kJ/molK)
ΔH°rxn = 0.2875kJ/molK
And replacing in (1) at 298K:
ΔG°rxn = 136.5kJ/mol - 298K×0.2875kJ/molK
<em>ΔG°rxn = +50.8 kJ/mol</em>
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Answer:
Por favor,no ponga exactamente lo que pongo,Trate de parafrasear.
La espectroscopia es el estudio de la interacción entre la materia y la radiación electromagnética en función de la longitud de onda o frecuencia de la radiación. La espectroscopia puede ser muy útil para ayudar a los científicos a comprender cómo un objeto como un agujero negro, una estrella de neutrones o una galaxia activa produce luz, qué tan rápido se mueve y de qué elementos está compuesto. Se pueden producir espectros para cualquier energía de la luz, desde ondas de radio de baja energía hasta rayos gamma de muy alta energía.
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