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Vlad1618 [11]
3 years ago
13

Assume the work done compressing the He gas is -63 kJ and the internal energy change of the gas is 79 kJ. What is the heat loss

or heat gain of this process?
Engineering
1 answer:
klemol [59]3 years ago
3 0

Answer:

Heat gain of 142 kJ

Explanation:

We can see that job done by compressing the He gas is negative, it means that the sign convention we are going to use is negative for all the work done by the gas and positive for all the job done to the gas. With that being said, the first law of thermodynamics equation will help us to solve this problem.

ΔU = Q + W ⇒ Q = ΔU -W

Q = 79 - (-63) = 142 kJ

Therefore, the gas gained heat by an amount of 142 kJ.

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Let’s define a new language called dog-ish. A word is in the lan- guage dog-ish if the word contains the letters ’d’, ’o’, ’g’ a
attashe74 [19]

Answer and Explanation:

// code

class Main {

   public static void main(String[] args) {

       /*

        *

        *

        * your code

        *

        */

       System.out.println(inDogish("aplderogad"));

       System.out.println(inXish("aplderogad", "dog"));

   }

   // returns true if the word is in dog-ish

   // returns false if word is not in dog-ish

   public static boolean inDogish(String word) {

       // first find d

       if (dogishHelper(word, 'd')) {

           // first find string after d

           String temp = word.substring(word.indexOf("d"));

           // find o

           if (dogishHelper(temp, 'o')) {

               // find string after o

               temp = temp.substring(temp.indexOf("o"));

               // find g

               if (dogishHelper(temp, 'g'))

                   return true;

           }

The output is attached below

       }

       return false;

   }

   // necessary to implement inDogish recursively

   public static boolean dogishHelper(String word, char letter) {

       // end of string

       if (word.length() == 0)

           return false;

       // letter found

       if (word.charAt(0) == letter)

           return true;

       // search in next index

       return dogishHelper(word.substring(1), letter);

   }

   // a generalized version of the inDogish method

   public static boolean inXish(String word, String x) {

       if (x.length() == 0)

           return true;

       if (word.length() == 0)

           return false;

       if (word.charAt(0) == x.charAt(0))

           return inXish(word.substring(1), x.substring(1));

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}

PS E:\fixer> java Main true true ne on

PS E:\fixer> java Main true true ne on

5 0
3 years ago
he mean weight of a breed of yearling cattle is 11871187 pounds. Suppose that weights of all such animals can be described by th
Tamiku [17]

Question

The mean weight of a breed of yearling cattle is 1187 pounds. Suppose that weights of all such animals can be described by the Normal model ​N(1187,78). ​

a) How many standard deviations from the mean would a steer weighing 1000 pounds​ be?

b) Which would be more​ unusual, a steer weighing 1000 ​pounds, or one weighing 1250 ​pounds? ​

Answer:

a. z = -2.40

A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.

b. z = 0.81

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Explanation:

a.

Let weight (in pounds) of the cattle be denoted by letter x:

z = (x - u)/ σ

Where u = mean and σ = standard deviation

u = 1187

σ = 78

x = 1000

Use z score formula to standardize the value of x:

z = (1000 - 1187)/78

z = -187/78

z = -2.397436

z = -2.40 ------_ Approximated

A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.

b.

x= 1250

z= (1250 - 1187)/78

z = 63/78

z = 0.807692

z = 0.81 --------- Approximated

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8 0
2 years ago
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