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Vlad1618 [11]
3 years ago
13

Assume the work done compressing the He gas is -63 kJ and the internal energy change of the gas is 79 kJ. What is the heat loss

or heat gain of this process?
Engineering
1 answer:
klemol [59]3 years ago
3 0

Answer:

Heat gain of 142 kJ

Explanation:

We can see that job done by compressing the He gas is negative, it means that the sign convention we are going to use is negative for all the work done by the gas and positive for all the job done to the gas. With that being said, the first law of thermodynamics equation will help us to solve this problem.

ΔU = Q + W ⇒ Q = ΔU -W

Q = 79 - (-63) = 142 kJ

Therefore, the gas gained heat by an amount of 142 kJ.

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Answer:

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P(X=6)=P(1,5)+P(2,4)+P(3,3)+P(4,2)+P(5,1)=

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P(X=9)=P(3,6)+P(4,5)+P(5,4)+P(6,3)=

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​

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1

​

P(X=11)=P(5,6)+P(6,5)=

36

2

​

=

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1

​

P(X=12)=P(6,6)=

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1

​

Therefore, the required probability distribution is as follows.

Then, E(X)=∑X

i

​

⋅P(X

i

​

)

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1

​

+3×

18

1

​

+4×

12

1

​

+5×

9

1

​

+6×

36

5

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+7×

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1

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1

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18

1

​

+12×

36

1

​

=

18

1

​

+

6

1

​

+

3

1

​

+

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5

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+

6

5

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+

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7

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E(X

2

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2

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⋅P(X

i

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1

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​

+81×

9

1

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+100×

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1

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+

2

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+

3

4

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+

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25

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49

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+

9

80

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​

+

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