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3 years ago

How the soild waste yeast is removed?

Chemistry

1 answer:

never [62]3 years ago

3 0

Hello User,

The solid waste of yeast is removed by water and ethanol.

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How can two objects of similar shape and size have different densities

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The mass and Volume is different even thought they have a similar shape and size

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A student increases the temperature of a 200 cm3 balloon from 60⁰C to 180⁰C. What should the new volume of the balloon be? Use t

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236 cm3 Is the correct answer..

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If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pre

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Answer:

627.4 mmHg

Explanation:

From Gay-Lussac law:

$\frac{p1}{t1} = \frac{p2}{t2}$

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$p2 = p1 \times \frac{t2}{t1}$

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3 years ago

A gas-filled weather balloon with a volume of 65.0 L is released at sea level where conditions are745 torr and 25 ºC. The balloo

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Answer:

It will reach to its maximum volume.

Explanation:

Using Ideal gas equation for same mole of gas as :-

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 65.0 mL

V₂ = ?

P₁ = 745 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 745 / 760 atm = 0.9803 atm

P₁ = 0.9803 atm

P₂ = 0.066 atm

T₁ = 25 ºC

T₂ = -5 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

T₂ = (-5 + 273.15) K = 268.15 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{0.9803}\times {65.0}}{298.15}=\frac{{0.066}\times {V_2}}{268.15}$

Solving for V₂ as:-

$V_2=\frac{0.9803\times \:65.0\times 268.15}{298.15\times 0.066}$

$V_2=\frac{17086.38392}{19.6779}$

V₂ = 868 L

Given that:- V max = 835 L

<u>Thus, it will reach to its maximum volume.</u>

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3 years ago

What is meant by the term effective nuclear charge

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