The solution would be like this for this specific problem:
4 NaOCl + S2O3{2-} + 2
OH{-} → 2 SO4{2-} + H2O + 4 NaCl
<span>(0.00456 L) x (0.100 mol/L
S2O3{2-}) x (4 mol NaOCl / 1 mol S2O3{2-}) x (100.0 mL / 25 mL) x </span><span>
<span>(74.4422 g NaClO/mol) = 0.54313 g </span></span>
<span>(5.00 mL) x (1.08 g/mL) =
5.40 g solution </span>
(0.54313 g) / (5.40 g) =
0.101 = 10.1%
So, the average percent by mass of NaClO in the
commercial bleach is 10.1%.
I have attached a picture which I think it is self-explanatory.
<span>Reflection is when light bounces off an object, while refraction is when light bends while passing through an object</span>
Answer:
yes? is there a question...
Explanation:
To determine the electrons gained in this redox reaction, we must balance the charges on the side containing the reduced substance and the side with oxidized substance. In this case, the reduced substance is Pb2+ and the oxidized substance is Cr. In each side, 6 electrons are gained or lose to balance the charges. The answer is 6 electrons.
Answer:
Option A - When |ΔHsolute| > |ΔHhydration|
Explanation:
A solution is defined as a homogeneous mixture of 2 or more substances that can either be in the gas phase, liquid phase, solid phase.
The enthalpy of solution can either be positive (endothermic) or negative (exothermic).
Now, we know that enthalpy is amount of heat released or absorbed during the dissolving process at constant pressure.
Now, the first step in thus process involves breaking up of the solute. This involves breaking up all the intermolecular forces holding the solute together. This means that the solute molecules are separate from each other and the process is always endothermic because it requires energy to break interaction. Thus;
The enthalpy ΔH1 > 0.
Thus, the enthalpy of the solute has to be greater than the enthalpy of hydration.
