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stiks02 [169]
3 years ago
6

What are the units for the spring constant, k?

Physics
1 answer:
Mnenie [13.5K]3 years ago
4 0

C. newtons/meter

Explanation:

The unit of spring constant K is newtons/meter.

The spring constant is also known as the stiffness.

    F = k e

F is the force

k is the spring constant

e is the extension.

 The unit of F is newtons

                    e is meters

Therefore, k becomes newtons/meter

  • Stiffness is the resistance to stretch of a body.

learn more:

Force brainly.com/question/3820012

#learnwithBrainly

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Ira Lisetskai [31]

Answer:

<h3>38,673.9N</h3>

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

<em>Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N</em>

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Answer:

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3 years ago
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3 years ago
A flywheel with radius of 0.400 mm starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2rad/s2.
charle [14.2K]

Answer: 0.00024\ m/s^2

Explanation:

Given

Radius of flywheel is r=0.4\ mm

Angular acceleration \alpha=0.6\ rad/s^2

For no change in radius, tangential acceleration is  given as

\Rightarrow a_t=a\lpha \times r

Insert the values

\Rightarrow a_t=0.6\times 0.4\times 10^{-3}\ m/s^2\\\Rightarrow a_t=2.4\times 10^{-4}\ m/s^2\ \text{or}\ 0.00024\ m/s^2

5 0
2 years ago
A spring stretches 3.5 cm when a 9 g object is hung from it. The object is replaced with a block of mass 26 g which oscillates i
evablogger [386]

Answer:

The period of motion  of new mass T = 0.637 sec

Explanation:

Given data

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Δx = 3.5 cm = 0.035 m

We know that spring force is given by

F = m g

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Spring constant

k = \frac{F}{x}

k = \frac{0.08829}{0.035}

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New mass(m_1) = 26 gm = 0.026 kg

Now the period of motion is given by

T = 2 \pi \sqrt{\frac{m}{k} }

T = 2 \pi \sqrt{\frac{0.026}{2.522} }

T = 0.637 sec

This is the period of motion  of new mass.

3 0
2 years ago
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