Answer:
![\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%20Kinetic%20%5C%20energy%20%5C%20%28KE%29%20%3D%2085%20%5C%20J%7D%20)
Given:
Mass (m) = 6.8 kg
Speed (v) = 5.0 m/s
To Find:
Kinetic energy (KE)
Explanation:
Formula:
![\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cbold%7B%5Csf%20KE%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20m%20%7Bv%7D%5E%7B2%7D%20%7D%7D)
Substituting values of m & v in the equation:
![\sf \implies KE = \frac{1}{2} \times 6.8 \times {5}^{2}](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20KE%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%206.8%20%5Ctimes%20%20%7B5%7D%5E%7B2%7D%20)
![\sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 3.4 \times 25](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20KE%20%3D%20%5Cfrac%7B1%7D%7B%20%5Ccancel%7B2%7D%7D%20%20%5Ctimes%20%20%5Ccancel%7B2%7D%20%5Ctimes%203.4%20%5Ctimes%2025%20)
![\sf \implies KE =3.4 \times 25](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20KE%20%3D3.4%20%5Ctimes%2025%20)
![\sf \implies KE = 85 \: J](https://tex.z-dn.net/?f=%20%5Csf%20%5Cimplies%20KE%20%3D%2085%20%5C%3A%20J)
I think you can google this because I really don’t know the answer I’m so sorry
u= 215 km/hr = 215 * 1000/ 3600 = aprx 60m/s
v=0
t=2.7sec
v= u - at
u= at
60/2.7 = 22.23 m/s^2
Hope it helps
Ok i will answer for real this time. Please give me brainliest.
<span>The Answerr is:
5.12*10^15. Since e=h*f, f=e/h. 3.4*10^(-18)/h.
</span>i am so sorry i was doing a challenge and i needed answers to get 100 pts.
Hope I Helped
~TeenOlafLover <3