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zhuklara [117]
3 years ago
10

What kind of volcanoes form from subduction boundaries

Chemistry
2 answers:
pishuonlain [190]3 years ago
8 0
Composite volcanoes, stratovolcanoes,<span> form from subduction boundaries.

In subduction zones, an oceanic plate subducts beneath a continental plate. A volcanic arc which is a series of volcanoes can form above the subduction zones where magma forms and rises from the friction of the plates rubbing against each other.</span>
Mashutka [201]3 years ago
3 0
Composite volcanoes and stratovolcanoes form from subduction boundaries
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Answer:

See the answer below

Explanation:

<em>First, it should be understood that an endothermic reaction is one that absorbs energy in the form of heat from the surrounding.</em> The products of endothermic reactions usually have higher energy than their reactants. Hence, the ΔH° which is referred to as the enthalpy change is usually positive.

<u>Forgetting to cover the coffee-cup calorimeter means some of the heat energy absorbed by the reactants would be exchanged back to the surroundings - a loss.</u> It also means that the enthalpy change would be smaller compared to if the cup had been covered because some of the heat has been lost to the surrounding.

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Show the calculation of the mole fraction of each gas in a 1.00 liter container holding a mixture of 8.65 g of CO2 and 4.32 g of
Vlad1618 [11]

Answer:

0.745 and 0.245

Explanation:

Mole fraction (χ) is  the number of moles of a component divided by the total number of moles in a mixture.  

We must calculate the moles of each component.  

Let CO₂ be Gas 1 and SO₂ be Gas 2.

1. Calculate the moles of each gas.

\text{n} _{1} = \text{8.65 g} \times \dfrac{\text{1 mol}}{\text{44.01 g}} = \text{0.1965 mol}\\\\\text{n} _{2} = \text{4.32 g} \times \dfrac{\text{1 mol}}{\text{64.06 g}} = \text{0.067 44 mol}

2. Calculate the total moles.

n_{\text{tot}} = \text{n}_{1} + \text{n}_{2} = \text{0.1965 mol} +\text{0.067 44 mol} = \text{0.2640 mol}

3. Calculate the mole fraction of each component

\chi_{1} =\dfrac{0.1965}{0.2640} = \mathbf{0.745}\\\\\chi_{2} =\dfrac{0.06744}{0.2640} = \mathbf{0.255}

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Ampere is apart of the metric unit so it would be reasonable for it to be a base unit.

I hope this helped!
5 0
3 years ago
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