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melisa1 [442]
4 years ago
14

An object is pulled along the ground by exerting a force of 35 pounds a rope that makes a 10° angle with the ground. How much wo

rk is done dragging the object 13 feet?
Physics
1 answer:
GREYUIT [131]4 years ago
8 0
<h2>Answer:</h2>

Workdone = 601.33 Nm

<h2>Explanation:</h2>

Workdone = Force(F) x horizontal distance(d).

Wordone = F x d

Where F is the horizontal component of the force

Force = 35 pounds

Recall that;

1 pound force = 4.4N

=> 35 pounds = 35 x 4.4N = 154N

=> Force = 154N

But since the rope makes a 10⁰ angle with the ground,

The horizontal component of the force F is  Force x  cos10⁰

=> F = 154 cos 10⁰

=> F = 154 x 0.9848

=> F = 151.66N

Horizontal distance (d) = 13 feet

Recall that;

1 foot = 0.305m

=> 13 feet = 13 x 0.305m = 3.965m

=> d = 3.965m

=> Substituting the values of F and d into the equation above, we have;

Workdone = F x d

Workdone = 151.66N x 3.965m

Workdone = 601.33Nm

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4 0
3 years ago
A 550N object has a coefficient of .012 against a smooth surface. What
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Vertically, the object is in equilibrium, so that the net force in this direction is

∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0

where <em>n</em> is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is <em>mg</em> = 550 N, so <em>n</em> = 550 N as well.

Horizontally, the net force would be

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