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Ne4ueva [31]
4 years ago
6

if the atomic number of Potassium is 19 and its mass is 39 what will be the number of electrons protons and neutrons and atoms a

lso give its symbol and sure its electronic configuration pictorially​
Chemistry
1 answer:
shtirl [24]4 years ago
3 0

Answer:

Explanation:

Symbol: K

Protons = 19

Electrons in an atom: 19

Neutrons: 39 - 19 = 20

Draw the nucleus at the center. Label it with 19 Protons and 20 Neutrons.

Draw a circle around the nucleus.

Put two dots opposite each other on the circle's circumference.

Draw another circle with its center at the nucleus bigger than you first circle.

Space 8 electrons around the circumference.

Draw a third circle like the other 2 only bigger.

Space 8 electrons around this circle's circumference.

Draw 1 more circle bigger than the third circle.

It has 1 electron.

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Can you type it out the picture is too blurry to read, sorry. 
4 0
3 years ago
If the concentration of the HCl used in your titration was 1.00 M and you used 23.68 mL to reach the endpoint, calculate the con
drek231 [11]

Answer: The concentration of the OH-, CB = 0.473 M.

Explanation:

The balanced equation of reaction is:

2HCl + Ca(OH)2 ===> CaCl2 + 2H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2 (from the balanced equation of reaction)

NB is the number of mole of base = 1 (from the balanced equation of reaction)

CA is the concentration of acid = 1M

CB is the concentration of base = to be calculated

VA is the volume of acid = 23.65 ml

VB is the volume of base = 25mL

Substituting

1×23.65/CB×25 = 2/1

Therefore CB =1×23.65×1/25×2

CB = 0.473 M.

6 0
3 years ago
What is the technique for calculating the age of remains from the amount of C-14 that is left in once alive living things?
Marizza181 [45]

Carbon 14 dating? is that one of your choices

5 0
4 years ago
Read 2 more answers
the combustion of a sample butane, C4H10 (lighter fluid) produced 2.46 grams of water. how many moles of water formed
enyata [817]
2C_4H_{10}+13O_2 ⇒ 8CO_2 + 10H_2O

n= \frac{m}{M} =  \frac{m}{2M(H)+M(O)}= \frac{2,46}{2*1,0+16,0}  = 0,14mol

So 0,14mol are formed.


6 0
4 years ago
For each chemical equation below, write the number of product molecules that will form from the reaction.
Gekata [30.6K]

Answer:

a. 5 moles of CO₂

b. 2 moles of NaCl

c. 3 moles of H₂CO₃

Explanation:

1a. Carbon reacts with oxygen to produce carbon dioxide according to equation below:

C + O₂ ----> CO₂

From the equation of reaction, one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.

In the given reaction, therefore, 5 moles of carbon will only react with 5 moles of oxygen to produce 5 moles of carbon dioxide. Oxygen is in excess, carbon is the limiting reactant and 5 moles of carbon dioxide are produced. The equation is given below :

5 C + 6 O₂ ---> 5 CO₂

1b. Sodium reacts with chlorine to produce sodium chloride according to the equation below:

2 Na + Cl₂ ---> NaCl

From the equation of reaction, 2 moles of sodium reacts with one mole of chlorine to produce one mole of sodium chloride.

In the given reaction, therefore, 4 moles of sodium will react with only 2 moles of chlorine to produce 2 moles of sodium chloride. Chlorine is in excess, sodium is the limiting reactant and 2 moles of sodium chloride are produced. The equation is given as follows: 4 Na + 8 Cl₂ ---> 2 NaCl

1c. Carbon dioxide reacts with water to produce carbonic acid according to the equation: CO₂ + H₂O ---> H₂CO₃

From the equation of reaction one mole of carbon dioxide reacts with one mole of water to produce one mole of carbonic acid.

In the given reaction, therefore, 3 moles of carbon dioxide will react with only 3 moles of water to produce 3 moles of carbonic acid. Water is in excess, carbon dioxide is the limiting reactant and 3 moles of carbonic acid are produced. The equation is given as follows: 3 CO₂ + 4 H₂O ---> 3 H₂CO₃

4 0
3 years ago
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