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Ne4ueva [31]
4 years ago
6

if the atomic number of Potassium is 19 and its mass is 39 what will be the number of electrons protons and neutrons and atoms a

lso give its symbol and sure its electronic configuration pictorially​
Chemistry
1 answer:
shtirl [24]4 years ago
3 0

Answer:

Explanation:

Symbol: K

Protons = 19

Electrons in an atom: 19

Neutrons: 39 - 19 = 20

Draw the nucleus at the center. Label it with 19 Protons and 20 Neutrons.

Draw a circle around the nucleus.

Put two dots opposite each other on the circle's circumference.

Draw another circle with its center at the nucleus bigger than you first circle.

Space 8 electrons around the circumference.

Draw a third circle like the other 2 only bigger.

Space 8 electrons around this circle's circumference.

Draw 1 more circle bigger than the third circle.

It has 1 electron.

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Answer:

Hydrogen

Explanation:

It is considered a special element due to its flexibility in giving up & taking in electrons, therefore making it good for organic & inorganic chemistry. Hydrogen has only one proton and one electron and is the only element which has no neutrons. it is considered as the simplest element in the universe and gives a valid reason for it to be the most abundant and common element in the universe.

Hoped this helped! If this doesn't fit your 80 word count, you could shorten it.

5 0
3 years ago
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Answer:

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Explanation:

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Define the boiling and evaporation using kinetic theory
expeople1 [14]

Answer:

Explanation:

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5 0
3 years ago
What is the pH of a 0.0042 M hydrochloric acid solution?
babymother [125]

Answer:

E) 2.38

Explanation:

The pH of any solution , helps to determine the acidic strength of the solution ,

i.e. ,

  • Lower the value of pH , higher is its acidic strength

and ,

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pH is given as the negative log of the concentration of H⁺ ions ,

hence ,

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From the question ,

the concentration of the solution is 0.0042 M , and being it a strong acid , dissociates completely to its respective ions ,

Therefore , the concentration of H⁺ = 0.0042 M .

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