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3 years ago

If suddenly the force of gravity of the sun stopped acting on the planets, in what kind of path would the planets move?

1 answer:

4 0

Each planet would instantly start moving away from the sun, at a constant speed and in a straight line, but NOT a straight line directly away from the sun. The straight line would start exactly where the planet is when gravity disappears, and its direction is TANGENT to the original orbit, continuing on in the direction the planet was moving when the sun's gravity shut off.

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If Angle "a" is 25°, Angle "b" is:

Leokris [45]

I would say B but I have no clue

6 0

3 years ago

If the units of your answer are kg ∙ m2/s3, which of the following types of quantities could your answer be?

kirza4 [7]

Answer:

D. power

Explanation:

kg represents mass

(m/v)² represents velocity squared

Then kg·m²/s² represents mass·velocity² = kinetic energy or potential energy or work.

kg·m²/s³ will be the rate of doing work, which is power

4 0

2 years ago

Read 2 more answers

What is the magnitude of velocity for a 2000 kg car possessing 3000 kgm/s of momentum

Alex

For this case we have that by definition, the momentum is given by:

$p = mv$

Where,

m: mass
v: speed

Therefore, replacing values we have:

$3000 = (2000) v$

From here, we clear the value of the speed:

$v = \frac {3000} {2000}\\v = 1.5 \frac {m} {s}$

Answer:

The magnitude of velocity is:

$v = 1.5 \frac {m} {s}$

4 0

3 years ago

Read 2 more answers

Mass m moves to the right with speed =v along a frictionless horizontal surface and crashes into an equal mass m initially at re

Amiraneli [1.4K]

After the collision the magnitude of the momentum of the system is Mv

Given:

mass of 1st object = M

speed of 1st object = v

mass of 2nd object = M

speed of 2nd object = 0

To Find:

magnitude of the momentum after collision

Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.

Applying conservation of linear momentum

Mv + M(0) = 2MV

Mv = 2MV

V = v/2

So, after collision momentum is

p = 2MV = 2xMxv/2 = Mv

So, after collision momentum is Mv

Learn more about Momentum here:

brainly.com/question/1042017

#SPJ4

4 0

1 year ago