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Semenov [28]
3 years ago
8

What is the density (g/L) of CHCl3 vapor at 1.00 atm and 298 K?

Chemistry
1 answer:
Scrat [10]3 years ago
4 0

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

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Determine which of these properties would distinguish these two substances: (a) boiling point; (b) combustion analysis results;
Nutka1998 [239]

Answer:

(a) boiling point

(d) density at a given temperature and pressure.

Explanation:

Isomers are compounds that have the same molecular formula but different structural formulas. They differ in chemical and physical properties depending on the type of isomerism displayed by the compounds.

The compounds stated here are structural or constitutional isomers hence they possess different boiling points and densities at a given temperature and pressure owing to structural differences in the molecules.

Since they have the same molecular formula, they must yield the same result during combustion analysis and they must have the same molecular weight.

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3 years ago
What are some of the activities performed during experiment​
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6 0
3 years ago
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What statement is true about ionic compounds
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They are made up of particles that are arranged in a repeating pattern.
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3 years ago
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A neutron collides with a nitrogen atom, resulting in a transmutation. Balance the equation. Superscript 1 Subscript 0 Baseline
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A is 14

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Explanation:

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7 0
2 years ago
Which of the following reasons best explains why it is possible to separate a 1:1 mixture of 1-chlorobutane and 1-butanol by fra
KatRina [158]

Answer:

The boiling point of 1-chlorobutane is substantially lower than that of 1-butanol

Explanation:

Fractional distillation is a separation process based on difference in boiling point of two compounds.

1-chlorobutane is a polar aprotic molecule due to presence of polar C-Cl bond. Hence  dipole-dipole intermolecular force exists in 1-chlorobutane as a major force.

1-butanol is a polar protic molecule. Hence dipole-dipole force along with hydrogen bonding exist in 1-butanol.

Therefore intermolecular force is stronger in 1-butanol as compared to 1-chlorobutane.

So, boiling point of 1-butanol is much higher than 1-chlorobutane.

Hence mixture of 1-chlorobutane and 1-butanol can be separated by fractional distillation based on difference in boiling point.

So, option (D) is correct.

6 0
3 years ago
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