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aalyn [17]
3 years ago
14

Sound travels in a medium of density 4.2e3 kg/m3 with a speed of 4.le3 m/s. Calculate the bulk modulus of the medium. (1 point)

A. 7.06e10 Pa B. 5.194e10 Pa C. 2.259e10 Pa D. 9.736e10 Pa E. 11.287e10 Pa
Physics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer : The correct option is, (A) 7.06\times 10^{10}Pa

Explanation :

The formula used for speed of sound wave is:

v=\sqrt{\frac{B}{\rho}}

where,

v = speed of sound wave = 4.1\times 10^3m/s

\rho = density of medium = 4.2\times 10^3kg/m^3

B = bulk modulus = ?

As the formula is,

v=\sqrt{\frac{B}{\rho}}

Squaring on both the sides, we get:

B=v^2\times \rho

Now put all the given values in the above formula, we get:

B=(4.1\times 10^3m/s)^2\times (4.2\times 10^3kg/m^3)

B=7.06\times 10^{10}Pa

Therefore, the bulk modulus of the medium is 7.06\times 10^{10}Pa

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A 68 kg object, starting from rest, travels from point A to point B at a rate of 30 m/s in 2 hours. What is the applied force on
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Answer:

\huge\boxed{\sf F = 0.28\ N}

Explanation:

<h3>Given Data:</h3>

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Time = 2 hours = 2 × 60 × 60 = 7200 s

<h3>Required:</h3>

Force = F = ?

<h3>Formula to be used:</h3>

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<h3>Solution:</h3>

\displaystyle F = \frac{(68)(30)}{7200} \\\\F = \frac{2040}{7200} \\\\F = 0.28 N\\\\\rule[225]{225}{2}

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Answer:

g'=63.74\ m/s^2

Explanation:

It is given that,

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Weight of a person is given by the following formula as :

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g' is the acceleration due to gravity on that planet. So,

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g'=\dfrac{5320\ N}{83.46\ kg}                

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So, the acceleration due to gravity on that planet is 63.74\ m/s^2. Hence, this is the required solution.                                                                    

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Explanation:

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