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aalyn [17]
3 years ago
14

Sound travels in a medium of density 4.2e3 kg/m3 with a speed of 4.le3 m/s. Calculate the bulk modulus of the medium. (1 point)

A. 7.06e10 Pa B. 5.194e10 Pa C. 2.259e10 Pa D. 9.736e10 Pa E. 11.287e10 Pa
Physics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer : The correct option is, (A) 7.06\times 10^{10}Pa

Explanation :

The formula used for speed of sound wave is:

v=\sqrt{\frac{B}{\rho}}

where,

v = speed of sound wave = 4.1\times 10^3m/s

\rho = density of medium = 4.2\times 10^3kg/m^3

B = bulk modulus = ?

As the formula is,

v=\sqrt{\frac{B}{\rho}}

Squaring on both the sides, we get:

B=v^2\times \rho

Now put all the given values in the above formula, we get:

B=(4.1\times 10^3m/s)^2\times (4.2\times 10^3kg/m^3)

B=7.06\times 10^{10}Pa

Therefore, the bulk modulus of the medium is 7.06\times 10^{10}Pa

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Answer:

The potential difference is 121.069 V

Solution:

As per the question:

Diameter of the cylinder, d = 9.0 cm = 0.09 m

Length of the cylinder, l = 40 cm = 1.4 m

Average Resistivity, \rho = 5.5\ \Omega-m

Current, I = 100 mA = 0.1 A

Now,

To calculate the potential difference between the hands:

Cross- sectional Area of the Cylinder, A = \pi (\frac{d}{2})^{2} = 6.36\times 10^{- 3}\ m^{2}

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4 0
3 years ago
Its not b...................
vladimir1956 [14]

sir what's the question you have all you wrote is it's not b

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The resistance between A and B is 10 ohms.
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