Explanation:
Below is an attachment containing the solution.
Given parameters:
Initial velocity of eraser = 5.0m/s
Time = 7.0s
Unknown:
Final velocity = ?
Solution:
Since we have been given the initial velocity and duration of the throw, we can apply the appropriate motion equation to solve this problem.
V = U - 2gt
where V is the final velocity
U is the initial velocity
g is the acceleration due to gravity = 9.8m/s²
t is the time taken
V = U - gt
V = 5 - (9.8)(7)
V = -63.6 or -64m/s
The velocity is -64m/s
Answer:
θr = 55.2 °
Explanation:
The law of reflection states that the angle of incidence and the angles of reflection is the same.
Let's use trigonometry to find the angle between the reflected ray, where the horizontal distance x = 55.9 cm and the vertical distance is y = 38.9 cm
tan θ = y / x
tan θ = 38.9 / 55.9
θ = tan⁻¹ (0.6959)
θ = 34.8°
This angle is measured with respect to the x-axis (horizontal), but in general the angles in optics are measured from the y-axis so that the angle is
θ = 90 - 34.8
θr = 55.2 °
Answer:
v= 3.18 m/s
Explanation:
Given that
m= 150 g = 0.15 kg
M= 240 g = 0.24 kg
Angular speed ,ω = 150 rpm
The speed in rad/s
ω = 15.7 rad/s
The distance of center of mass from 150 g
r= 20.30 cm
The speed of the mass 150 g
v= ω r
v= 20.30 x 15.7 cm/s
v= 318.71 cm/s
v= 3.18 m/s
Answer:
Are you looking for the formula? because if so:
M L^2 T^-3 I^-2
Explanation:
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