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2 years ago

Answer all questions will mark as brainiest

Physics

1 answer:

Drupady [299]2 years ago

7 0

11:C) sound travels fastest in solids
12:A) Sound needs a medium to travel
13:D) Just like with cupped hands

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This equation shows the reaction that occurs when calcium carbonate

yarga [219]

Answer:

a. endothermic

Explanation:

The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.

Endothermic changes involves absorption of heat from the surrounding.
The surrounding becomes colder at the end of the reaction.
When heat is on the reactant side, it suggests a reaction that requires a considerable input of energy.

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2 years ago

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Can someone help me with this ASAP

Lilit [14]

4. B Mantle. 5. C Solid.

Explanation:

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2 years ago

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What is meant by the phrase "a consistent method of measurement"?

julia-pushkina [17]

A measurement that will always give the same answer.

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2 years ago

What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?

IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as $m_{1} \ and\ m_{2}\ respectively$

$Let\ m_{1} =1 kg\ and\ m_{2} =2 kg$

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

$m_{1} g-T=m_{1} a$ [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction $[\mu]=0.13$

$Hence\ the\ frictional\ force\ F=\mu N$

$F=\mu m_{2} g$

Hence the net force acting on the body having mass 2 kg-

$T-\mu m_{2} g=m_{2} a$ [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

$m_{1} g-T=m_{1}a$ [1]

$T-\mu m_{2}g= m_{2} a$ [2]

---------------------------------------------------

$[m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a$

$a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g$

$a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2$

$a=\frac{0.74}{3} *9.8\ m/s^2$

$a=2.417 m/s$ [ans]

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2 years ago

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For a constant applied force, how does increasing the mass of an object affect it acceleration?

Inessa05 [86]

As the mass of an object increases with a constant force applied to it, its acceleration will ultimately decrease

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2 years ago