Answer: Theoretical yield of
produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :


The balanced chemical equation is:
According to stoichiometry :
2 moles of
produce = 3 moles of 
Thus 0.28 moles of
will produce=
of
Mass of 
Thus theoretical yield of
produced by 8.96 g of S is 33.6 g
Answer:
25.2 kJ
Explanation:
The complete question is presented in the attached image to this answer.
Note that, the heat gained by the 2.00 L of water to raise its temperature from the initial value to its final value comes entirely from the combustion of the benzoic acid since there are no heat losses to the containing vessel or to the environment.
So, to obtained the heat released from the combustion of benzoic acid, we just calculate the heat required to raise the temperature of the water.
Q = mCΔT
To calculate the mass of water,
Density = (mass)/(volume)
Mass = Density × volume
Density = 1 g/mL
Volume = 2.00 L = 2000 mL
Mass = 1 × 2000 = 2000 g
C = specific heat capacity of water = 4.2 J/g.°C
ΔT = (final temperature) - (Initial temperature)
From the graph,
Final temperature of water = 25°C
Initial temperature of water = 22°C
ΔT = 25 - 22 = 3°C
Q = (2000×4.2×3) = 25,200 J = 25.2 kJ
Hope this Helps!!!
Answer:
d = Hydrogen and oxygen are being formed.
Explanation:
When current is passed through the water electrolysis take place.
Water is splitted into hydrogen and oxygen gas. Because of this formation bubbles are formed.
At cathode:
2H₂O + 2e⁻ → H₂ + 2OH⁻
Cathode is negatively charged and reduction take place on it.
At anode:
4OH⁻ → O₂ + 2H₂O + 4e⁻
Anode is positively charged and oxidation take place on it.
The over all reaction can be written as:
Chemical equation:
2H₂O (electricity) → 2H₂ + O₂
First, we have to calculate the number of moles of H2SO4 in the solution:
V=60 mL = 0.06 L
c=5.85 mol/L
n=V×c=0.06×5.85=0.351 mol
Then we need to find the molar mass of H2SO4:
2×Ar(H) + Ar(S) + 4×Ar(O) =
=2 + 32 + 64 = 98 g/mol
Finally, we need to find the mass of H2SO4:
m=0.351 × 98 = 34.398 g