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n200080 [17]
2 years ago
5

Which of the following is a heterogeneous mixture?

Chemistry
2 answers:
Contact [7]2 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

A mixture whose components differ in proportion or simply whose constituent particles can be easily separated from each other is known as a heterogeneous mixture.

For example, a mixture of water and sand is a heterogeneous mixture as it's constituent particles vary in proportion.

Therefore, out of the given options a jar of mixed nuts is a heterogeneous mixture.

Softa [21]2 years ago
3 0
A heterogeneous mixture is a mixture that it's components can be easily seen and separated. 

c. a jar of mixed nuts

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2 years ago
When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac
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<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

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Determine the moles of methane

\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}

Determine the mass of water produced

\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0
1 year ago
A solution contains 22.4 g glucose (C6H12O6 ) dissolved in 0.500 L of water. What is the molality of the solution
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Answer:

Molality is 0.25 m

Explanation:

Molality → Moles of solute / kg of solvent

We need the moles of solute → 0.124 moles

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We need the mass of solvent in kg. We determine the mass of solvent with density.

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Mass = Density . volume → 1 g/mL . 500 mL = 500 g

If we convert the mass in g to kg → 500 g . 1kg / 1000 g = 0.5 kg

In conclussion, molality → 0.124 mol / 0.5 kg = 0.25 m

8 0
3 years ago
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