Alka-seltzer in an antacid that contains a mixture of sodium bicarbonate and citric acid. When the tablet is dissolved in water, the reactants which are in solid form in tablet become aqueous and react with each other.
During this reaction, Carbon Dioxide gas is evolved which causes the reaction mixture to fizz. The equation is given below.
Rate of the above reaction is affected by the Temperature.
As the temperature increases , the rate of the reaction increases. This happens because at higher temperature, the collisions between reacting species are more which result in formation of product in less time. This increases the rate of reaction.
We have been given equal volumes of water for each beaker. But the temperature of beaker c is 80°C which is the highest temperature. That means the reaction in beaker c is fastest.
Whereas beaker a is at lowest temperature (30°C) , therefore the reaction in beaker a would be slowest .
Therefore the answer that correctly orders the reaction rates from fastest to slowest reaction is beaker c > beaker b > beaker a
Answer:change in energy of the electron=3.052x 10^-19J
which energy level does it move= level 2 , n=2
Explanation:
Using the formulae
1/λ = R (1/n1²- 1/n2²)
Where λ= 656.27 nm
1 nm = 1 x 10^-9 m
656.27 nm = 656.27 x 1 x 10^-9 =6.5726 x 10^-7
R =Rydberg constant = 1.0967 x 10^7m-1
1/λ = R (1/n1²- 1/n2²)
1/6.5726 x 10^-7=1.0967 x 10^7(1/n1²- 1/3²)
1/n1²=(1/6.5726 x 10^-7 x 1/1.0967 x 10^7) + 1/9
1/n1²=1,521,467.9 x 9.118x10^-8 + 0.1111
1/n1² =0.2498
n1²= 1/0.2498 =4
n1= 
= 2
it moves to energy level 2
b) Change in energy =ΔE = Rhc (1/n1²- 1/n2²)
Where R==Rydberg constant = 1.0967 x 10^7m-1
h = Planck constant = 6.626x 10^-34js
c = speed of light = 3.0 x 10^8 x m/s
ΔE = Rhc (1/n1²- 1/n2²)
=1.0967 x 10^7m-1 x6.626x 10^-34js X 3.0 x 10^8 x m/s (1/2² - 1/3²)
=2.18 x 10-18 x ( 1 /4 - 1/9)
=3.052x 10^-19J
Answer: 32.94 g
Explanation: It's stoichiometry problem so balanced equation is required. The balanced equation is given below:
From the balanced equation, krypton and chlorine react in 1:2 mol ratio. We will calculate the moles of each reactant gas using ideal gas law equation(PV = nRT) and then using mol ratio the limiting reactant is figured out that helps to calculate the amount of the product formed.
for Krypton, P = 0.500 atm and for chlorine, P = 1.50 atm
V = 15.0 L
T = 350.8 + 273 = 623.8 K
For krypton, 
n = 0.146 moles
for chlorine, 
n = 0.439
From the mole ratio, 1 mol of krypton reacts with 2 moles of chlorine. So 0.146 moles of krypton will react with 2 x 0.146 = 0.292 moles of chlorine.
Since 0.439 moles of chlorine are available, it is present in excess and hence the limiting reactant is krypton.
So, the amount of product formed is calculated from moles of krypton.
Molar mass of krypton tetrachloride is 225.61 gram per mol.
There is 1:1 mol ratio between krypton and krypton tetrachloride.
= 32.94 g of 
So, 32.94 g of the product will form.
Answer:
combustion reaction, because the products are CO2 and H2O
Answer:
[Ag+] = [NO3-] = 0.700M
0.555M = [Na+] = [I-]
Explanation:
To solve this question we need to find the moles of sodium iodide, NaI, using its molar mass -. With the moles and the volume we can find the molarity of Na+ and I-. The molarity of the ions of silver nitrate, AgNO3 doesn't change because we are assuming the volume doesn't change:
<em>Molarity Ag⁺ = Molarity NO₃⁻ = 0.700M</em>
<em>Moles NaI -Molar mass: 149.89g/mol-</em>
20.8g NaI * (1mol/149.89g) = 0.0139 moles NaI
<em>Molarity:</em>
0.0139 moles NaI / 0.250L = <em>0.555M = [Na+] = [I-]</em>
