All categories

4 years ago

Which of the following statements is true?

Chemistry

1 answer:

pashok25 [27]4 years ago

3 0

The answer is longitudinal waves more particles at right angles

You might be interested in

Convert 0.02 g/mL to the unit g/L.

Vilka [71]

0,02 g/mL = 20 g/L

:)

4 0

3 years ago

Uranium-236 is _____. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-

nata0808 [166]

<span>Uranium-236 is intermediate nuclei. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb.

Following is the reaction involved in above process:

</span> $^{235}U$ + $^{1}n$ → $^{236}U$ → $^{144}Ba$ + $^{89}Kr$ + 3 $^{1}n$ <span> + 177 MeV
</span>
Here,
$^{235}U$ = Fission material,
$^{1}n$ = projectile,
$^{236}U$ = intermediate nuclei,
$^{144}Ba$ and $^{89}Kr$ = Fission product

8 0

3 years ago

Read 2 more answers

What is the volume of 4.78g of O2 gas at STP?

My name is Ann [436]

Answer:

Explanation:

The trick here is to realize that if you know the volume of a gas at STP, you can use the fact that

mole of any ideal gas occupies

22.7 L

under STP conditions to calculate how many moles of gas you have in your sample.

Under STP conditions:

1 mole of an ideal gas = 22.7 L

−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−

In your case, you know that your sample of gas occupies

2.28 L

under STP conditions, which are currently defined as a pressure of

100 kPa

and a temperature of

∘

This means that your sample will contain

2.28

⋅

molar volume of a gas at STP



1 mole gas

22.7

0.10044 moles gas

Now, the molar mass of the gas is the mass of exactly

mole of the gas. In your case, you know that you get

3.78 g

for every

0.10044

moles, which means that you have

mole

⋅

3.78 g

0.10044

moles

37.6 g

Since this is the mass of

mole of gas, you can say that the molar mass of the gas is

molar mass = 37.6 g mol

−

−−−−−−−−−−−−−−−−−−−−−−−

8 0

3 years ago

Read 2 more answers

The solubility of copper(i) chloride is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl (cucl=99.00 g mol-1).

garri49 [273]

Convert Mg to grams
1g =1000mg what about 3.91 Mg
= 3.91mg x 1g/1000mg= 3.91 x10^-3 g
moles= mass/molar mass
that is 3.91 x10^-3g /99 g/mol=3.95 x10^-5moles
concentration= moles / vol in liters

that is 3.95 x10^-5/100 x1000= 3.94 x10^-4M

equation for dissociation of CUCl= CUCl----> CU^+ +Cl^-

Ksp=(CU+)(CI-)
that is (3.95 x10^-4)(3.95 x10^-4)
Ksp= 1.56 x10^-7

3 0

3 years ago

Read 2 more answers

a rock is found to have a small amount of copper would you call the rock an ore of copper explain in 5-6 sentences

alexgriva [62]

Answer:

Answer: No. An ore is a rock having large amounts of a mineral. Minerals may or may not be commercially useful.

3 0

3 years ago