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Sav [38]
3 years ago
14

When you give the molecules in a gas sample more room to move,

Chemistry
2 answers:
astraxan [27]3 years ago
7 0
You didn’t post the whole question :/
motikmotik3 years ago
6 0
It becomes stays a gas particle just more spread out??
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What is “ location of the sweat glands “
kompoz [17]
Mostly found on the soles of feet, palms, forehead, cheeks and of course armpits they're also called eccrine sweat glands
8 0
3 years ago
A lab group was supposed to make mL of a acid solution by mixing a solution, a solution, and a solution. However, the solution w
MissTica

Question: The question is not complete. Find below the complete question and the answer.

Alab group was supposed to make 14 mL of a 36% acid solution by mixing a 20% solution, a 26% solution, and a 42% solution. However, the 20% solution was mislabeled, and was actually a 10% solution, so the lab group ended up with 14 mL of a 34% acid solution, instead. If the augmented matrix that represents the system of equations is given below, what are the volumes of the solutions that should have been mixed? mL

Volume of 20% solution= ?

Volume of 26% solution = ?

Volume of 42% solution= ?   Round to the nearest whole number ml

Answer:

Volume of 20% solution= 3 mL

Volume of 26% solution = 1 mL

Volume of 42% solution= 10 mL

Explanation:

Find attached of the calculations.

3 0
3 years ago
If you have a volume of 10.5 mL and a mass of 100. kg, what is the density?
erma4kov [3.2K]

Answer:

9.52 kg/mL

Explanation:

Density = mass/ Volume

= 100 kg/ 10.5 mL

= 9.523809524 kg/mL

OR

100 kg = 100 × 10^3 g

》Density = 100 × 10^3 g/ 10.5 mL

= 9523.809524 g/mL

3 0
3 years ago
Read 2 more answers
Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine
Roman55 [17]

second compound

Let molar mass of x is = X

Let molar mass of y is = Y

Moles of x in second compound = Mass / molar mass = 7 / X

Moles of y in second compound = Mass / molar mass = 4.5 / Y

For second compound  

7 / X : 4.5/ Y = 1:1

Therefore

X / Y = 7/4.5

Y / X = 4.5/ 7

The mass of x in first compound = 14g

moles of x in first compound = 14/X

Mass of y in first compound = 3

moles of y in first compound = 3 / Y

14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1

Thus molar ratio in first compound = moles of x / Moles of y = 3:2

Formula = x3y

6 0
3 years ago
Which statement correctly describes soil horizon C? A. It is considered the subsoil layer. B. It is the horizon with the smalles
kirill [66]

Answer:

i believe that the answer is c

Explanation:

I think its c because because its used as a bed rock layer

8 0
3 years ago
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