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4 years ago

Which answer best explains what happens to particles as their temperature rises?

2 answers:

8 0

Particles are always vibrating, as temperature rises, thermal energy is being released into the particles, so they start vibrating faster in order for them to release the thermal energy.

Serjik [45]4 years ago

5 0

Heat is a form of energy. As heat is added to a substance, the particles gain more energy, which becomes kinetic energy (energy of motion). This cause the particles to move and vibrate faster. The more heat, and therefore the more kinetic energy and more speed, that is added to a substance, the easier it is for particles to break free from it's state and evaporate.

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How much work is accomplished when a force of 250 N pushes a box across the floor for a distance of 50 meters?

IrinaK [193]

Work = force * distance
and newton*meters = Joule

In this case, work = 250N*50m = 12500 J

So the answer is D) 12,500 J

3 0

4 years ago

Consider a venturi with a small hole drilled in the side of the throat. This hole is connected via a tube to a closed reservoir.

Marina CMI [18]

Answer:

( $P_1-P_2$ )=1913.31 N/m^2

Explanation:

given:

$\frac{A_t}{A_1}$ =0.85

$V_1$ =90 m/s

γ∞=1.23 kg/m^3

solution:

since outside pressure is atm pressure vaccum can be defined by ( $P_1-P_2$ )

$V_1$ =√2( $P_1-P_2$ )/γ∞[ $\frac{A_t}{A_1}^2$ -1]

( $P_1-P_2$ )=1913.31 N/m^2

6 0

3 years ago

Argue as to why drivint on icy or snowy roads can be dangerous

Vika [28.1K]

Icy/Snowy roads have less friction than normal roads. This means that the wheels are less likely to stay positioned because of traction, and you will spin out of control

6 0

3 years ago

A person has a mass of 60 kg. What is the person’s weight in Newtons and in pounds?

liubo4ka [24]

Answer:

137.2 in pounds and in Newton's it's 588.399

3 0

3 years ago

Julie blows a bubble. At first, the pressure of the gas in the bubble is 4kPa. The bubble floats into the air and expands. When

Andrew [12]

Answer:

V₁ = 1.75 m³

Explanation:

Assuming the gas to be an ideal gas. At constant temperature, the relationship between the volume and temperature of an ideal gas is given by Boyle's Law as follows:

$P_{1}V_{1} = P_{2}V_{2}$

where,

P₁ = Initial Pressure of the Gas = 4 KPa

V₁ = Initial Volume of the Gas = ?

P₂ = Final Pressure of the Gas = 2 KPa

V₂ = Final Volume of the Gas = 3.5 m³

Therefore,

$(4\ KPa)V_{1} = (2\ KPa)(3.5\ m^{3})\\\\V_{1}=\frac{2\ KPa}{4\ KPa}(3.5\ m^{3})\\\\$

4 0

3 years ago