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disa [49]
3 years ago
6

A researcher wants to make a solution of agcl and water at 75 °c. for solid agcl at 75°c, ksp = 1.5 x 10-5.

Chemistry
1 answer:
mars1129 [50]3 years ago
7 0
A.)
dG = -(0.008314)(348K) (1.5 * 10-5)
dG = -(0.008314)(348K (-11.107)
dG = 32 kJ/mol (rounded from 32.14) 
--------
B.)
AgCl(s) >>>> Ag+ and Cl-
<span>Ksp = {Ag+}{Cl-} 
</span><span>1.5 * 10-5 = {Ag+}{Cl-}
</span>1.5 * 10-5 = {X}{X}
<span>X2 = 1.5 x 10-5 
</span>X={Ag+}{Cl-}
Sol / AgCl = 3.873E-3 litres/moles
<span>(3.873E-3 moles AgCl/Litre) (143.32 g AgCl / mol)= 0.56g AgCl</span>
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Answer: The hydroxide concentration of this sample is 3.85\times 10^{-7}

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When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.

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