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3 years ago

A swimming pool is 5.0 m long, 4.0 m wide and 3.0 m deep. Compute the force exerted by the water against

1 answer:

6 0

For the answer to the question above, ater weights 1000kg per meter cubed. the volume of the pool is part A is 5*4*3 = 60 meters cubed 
60*1000 = 60 000kg. the force from this is m*g = 60 000 * 9.81 = 588kN 

part B: 
volume: 4*4*3 = 48 meters cubed 
48 * 1000 = 48000kg 
F = 9.81*48000 = 470kN
I hope this helps.

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In the equation:

Ksenya-84 [330]

Answer:

B) 16 g

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3 years ago

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3 years ago

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You measure salt water in a tank to have a density of 1.02 g/mL. A balloon weighs 2.0 g and you weights have a mass of 30.0 g ea

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Weight of the balloon = 2.0 g

Six weights each of mass 30.0 g is added to the balloon.

Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g

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Calculating the volume from mass and density:

$182g*\frac{mL}{1.02g} =178mL$

Converting the volume from mL to cubic cm:

$178 mL * \frac{1cm^{3} }{1mL} =178cm^{3}$

Assuming the balloon to be a sphere,

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r = 3.49 cm

Radius of the balloon = 3.49 cm

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3 years ago

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Explanation:

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