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Ivanshal [37]
3 years ago
9

It is found that a 5.70 m segment of a long string contains three complete waves and has a mass of 180 g. The string is vibratin

g sinusoidally with a frequency of 55.0 Hz and a peak-to-valley distance of 19.0 cm. (The "peak-to-valley" distance is the vertical distance from the farthest positive position to the farthest negative position). Calculate the wavelenght.
Physics
2 answers:
iragen [17]3 years ago
8 0

Answer:

wavelength = 3.8 m

Explanation:

As we know that linear mass density is defined as the ratio of mass and length

so here we have

\mu = \frac{m}{L}

\mu = \frac{0.180}{5.70}

now we have

\mu = 0.0315 kg/m

Now it is given that string contains three complete waves

length of one segment on string is half of the wavelength

so here we have

3\frac{\lambda}{2} = 5.70 m

\lambda = 3.8 m

So wavelength of the wave on string is 3.8 m

Hoochie [10]3 years ago
3 0

Answer:

1.9 m.

Explanation:

Three complete waves in the length of 5.7 m

The distance traveled by one complete wave is called wavelength.

Thus, the distance traveled by one wave = 5.7 / 3 = 1.9 m

Thus, the wavelength is 1.9 m.

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A 5. 3 ft -ft-tall girl stands on level ground. The sun is 30 ∘ above the horizon. How long is her shadow?
slamgirl [31]

The trigonometric ratios are sine, cosine and tangent. We can use cosine to find the length of the shadow from the calculation as 1.7 ft.

<h3>What is trigonometric ratio?</h3>

The term trigonometric ratio has to do with sine, cosine and tangent which are used to solve problems that involve the right angled triangle.

Using the geometry of the right angle triangle, we can find the tangent of the angle 30 in order to obtain the length of the shadow.

Tan 30° = opp/3

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The length of the girl's shadow from the calculation is 1.7 ft.

Learn more about tangent: brainly.com/question/14022348

8 0
2 years ago
Waves can transfer energy through
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Answer:

electromagnetic waves

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3 0
3 years ago
An applied force of 50 N is used to accelerate an object, that weighs 73 N, to the right across a frictional surface. The object
Hunter-Best [27]

Answer:

5.38 m/s^2

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F = ma

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