What is the formula of a compound formed between iodine (I) and calcium (Ca)?
2 answers:
<u>Answer:</u> The chemical formula for the compound will be
<u>Explanation:</u>
Calcium is the 20th element of the periodic table having electronic configuration of
This element will loose 2 electrons and thus shows an oxidation state of +2 units.
Iodine is the 53rd element of the periodic table having electronic configuration of
This element requires 1 electron and thus shows an oxidation state of -1 units.
So, by criss-cross method, the oxidation state of the ions will get exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
Hence, the chemical formula for the compound formed will be
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Answer:
Kp = 0.81666
Explanation:
Pressure of PCl₅ = 0.500 atm
Considering the ICE table for the equilibrium as:
PCl₅ (g) ⇔ PCl₃ (g) + Cl₂ (g)
t = o 0.500
t = eq -x x x
--------------------------------------------- --------------------------
Moles at eq: 0.500-x x x
Given the pressure of PCl₅ at equilibrium = 0.150 atm
Thus, 0.500 - x = 0.150
x = 0.350 atm
The expression for the equilibrium constant is:
So,
x = 0.350 atm
Thus,
<u>Thus, Kp = 0.81666</u>