Answer:
The value of the correct angle of banking for the road is
°
Explanation:
Given data
Velocity (v) = 60 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
Radius = 150 m
The velocity of the car in this case is given by
![v = \sqrt{r g \tan \theta}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Br%20g%20%5Ctan%20%5Ctheta%7D)
![v^{2} = r g \tan \theta](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20r%20g%20%5Ctan%20%5Ctheta)
![\tan \theta = \frac{v^{2} }{rg}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%20%5Cfrac%7Bv%5E%7B2%7D%20%7D%7Brg%7D)
Put all the values in above formula we get
![\tan \theta = \frac{60^{2} }{(150)(9.81)}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%20%5Cfrac%7B60%5E%7B2%7D%20%7D%7B%28150%29%289.81%29%7D)
2.446
°
Therefore the value of the correct angle of banking for the road is
°
An example of a balanced force is two cards leaning against each other and not falling over, or two football players blocking each other but neither overpowering the other. An example of an unbalanced force is two cards leaning on each other then falling over, or two football players blocking each other, then one tackles the other.
Catalytic ozone destruction occurs in the stratosphere where the reactions involving bromine, chlorine, hydrogen, nitrogen and oxygen gases form compounds that destroy the ozone layer. The reactions uses a catalyst (speeds up the reaction) in a two step reaction. considering chlorine the reactions appears as follows;
step 1
Cl + O3 = ClO + O2
step 2
ClO + O = Cl + O2
Where by chlorine is released to destroy the ozone layer, this takes place many times even with the other elements (hydrogen, bromine, nitrogen) and the end result is a completely destroyed Ozone layer
No, one more group must get the same result as the other group. This will make it more reliable and reproducible.