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vivado [14]
4 years ago
14

When Jackson throws a tennis ball in a straight path, what two forces cause the ball to eventually stop moving?

Physics
2 answers:
Aleksandr-060686 [28]4 years ago
5 0

After Jackson lets go of the ball, there are two forces on it
that influence what it's going to do.  They are gravity and
air resistance.

Air resistance is just plain friction.  As long as the ball continues
to move through air, it loses kinetic energy to the air and gradually
slows down.

While the ball is in the air, there are no other forces on it that cause
it to stop moving. 

If you absolutely must have another one, it doesn't occur until the
ball hits the ground.  But that isn't even another force.  It's just more
friction, from scraping against concrete and grass.

Gravity pulls the ball down to the ground.  But gravity doesn't make
the ball stop moving.  In fact, gravity tries to make it move faster and
faster, and gravity would succeed if it weren't for all the friction that
the ball encounters.

Anon25 [30]4 years ago
3 0

Well, the force that originally caused it to start moving was inertia, but the  forces that cause it to stop are friction and gravity. Gravity pulls the object towards the center of the Earth, causing it to slow and eventually stop, and friction is the resistance between the ball and the ground (or whatever).

Hope this helps!

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A lunch pail is accidentally kicked off a steel beam on a building under construction. Suppose the initial horizontal speed is 1
vichka [17]

1) 26.6 m

Along the horizontal direction, the lunch pail is moving with a uniform motion (constant speed), since there are no forces acting in this direction.

Therefore, the distance travelled horizontally after a time t is given by:

d=v_x t

where we know

v_x = 1.50 m/s is the horizontal velocity

d = 3.50 m is the distance covered horizontally

Solving for t, we find the total time of the motion:

t=\frac{d}{v_x}=\frac{3.50}{1.50}=2.33 s

Now we know that the pail takes 2.33 s to fall to the ground. We can now consider the vertical motion of the pail, which is a free fall motion, so the vertical displacement is given by the equation

s=ut+\frac{1}{2}at^2

where, taking downward as positive direction:

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

Substutting t = 2.33 s, we find how fat the pail has fallen:

s=\frac{1}{2}(9.8)(2.33)^2=26.6 m

2) 10.7 m

In this case, we know instead the vertical displacement:

s=2.50\cdot 10^2 m = 250 m

Therefore, we can use the same equation again

s=ut+\frac{1}{2}at^2

To find the total time of motion:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(250)}{9.8}}=7.14 s

We know that along the horizontal direction, the velocity is constant:

v_x = 1.50 m/s

So, the horizontal distance covered in this time is

d=v_x t = (1.50)(7.14)=10.7 m

6 0
4 years ago
what is the vapor pressure of water if the total vapor pressure is 1.5 atm and the pressure of oxygen is 0.2 atm?
andreyandreev [35.5K]

Since the total pressure of each gas is the sum of the partial pressures of all the individual gases, the vapor pressure of oxygen is  1.3 atm.

From Dalton's law of partial pressure, the total pressure is the sum of the individual partial pressures of the gases;

PT = PA + PB + PC + --------

Given that;

Vapor pressure of oxygen = 0.2 atm

Total pressure = 1.5 atm

Vapor pressure of oxygen = ?

Partial pressure of oxygen =  1.5 atm - 0.2 atm = 1.3 atm

The vapor pressure of oxygen is  1.3 atm.

Learn more: brainly.com/question/2510654

8 0
3 years ago
What are atoms of the same element with different numbers of neutrons are called?
kenny6666 [7]

Answer:

Explanation:

Los átomos que tienen el mismo número de protones y electrones pero diferente número de neutrones se llaman isótopos. Los isótopos de un elemento dado tienen diferentes masas atómicas.

4 0
4 years ago
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Why is it impossible for us to observe any furthur than 13.7 billion light years in the universe??
Burka [1]
Because made it like that
7 0
3 years ago
A drunken sailor stumbles 600 meters north, 550 meters northeast, then 500 meters northwest. What is the total displacement and
beks73 [17]

We will make a graph to better understand the displacement of the individual. From the trigonometric properties we will find the required distances.

d_1 = \frac{450}{\sqrt{2}} = 318.198

d_2 = \frac{400}{\sqrt{2}} = 282.843

D = 500+d_1+d_2 = 1101.041

Displacement ,

x = \sqrt{1101.041^2+(318.198-282.843)^2}}

x = 1101.608m

The angle would be

\theta = cos^{-1} (\frac{1101.041}{1101.608})

\theta = E 1.838\° N

Therefore the displacement was of 1101.608m to a angle of 1.838° from East to North.

7 0
3 years ago
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