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DanielleElmas [232]

3 years ago

5

A 24-tooth gear has AGMA standard full-depth involute teeth with diametral pitch of 12. Calculate the pitch diameter, circular p

itch, addendum, dedendum, tooth thickness and clearance. All dimensions must be taken to 4 decimal places to account for manufacturing tolerances.

2 answers:

torisob [31]3 years ago

5 0

Answer:

Explanation:

Given:

Tooth Number, N = 24

Diametral pitch pd = 12

pitch diameter, d = N/pd = 24/12 = 2in

circular pitch, pc = π/pd = 3.142/12 = 0.2618in

Addendum, a = 1/pd = 1/12 =0.08333in

Dedendum, b = 1.25/pd = 0.10417in

Tooth thickness, t = 0.5pc = 0,5 * 0.2618 = 0.1309in

Clearance, c = 0.25/pd = 0.25/12 = 0.02083in

Oduvanchick [21]3 years ago

4 0

Answer:

• Pitch diameter = 2.0000in

• Circular pitch = 0.2618in

• Addendum = 0.0833in

• Dedendum = 0.1042in

• Tooth thickness = 0.1309 in

• Clearance = 0.02083 in

Explanation:

We are given:

Total number, N = 24

Diametral pitch, pd = 12 in

•to calculate pitch diameter, we use:

$d = \frac{N}{pd} =\frac{24}{12} = 2.0000 in$

•to calculate circular pitch, we have:

$P_c= \frac{pi}{pd} = P_c = \frac{3.142}{12}= 0.2618in$

•To calculate addendum:

$Addendum, a= \frac{1.0000}{pd} => \frac{1.0000}{12} = 0.0833in$

•Dedendum:

$b= \frac{1.2500}{pd}=> \frac{1.2500}{12} =0.1042in$

•Tooth thickness, t :

t = 0.5*pc

= 0.5*0.2618 = 0.1309in

•Clearance, c:

$c = \frac{0.2500}{pd} => \frac{0.2500}{12} = 0.2083in$

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