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DanielleElmas [232]
3 years ago
5

A 24-tooth gear has AGMA standard full-depth involute teeth with diametral pitch of 12. Calculate the pitch diameter, circular p

itch, addendum, dedendum, tooth thickness and clearance. All dimensions must be taken to 4 decimal places to account for manufacturing tolerances.
Engineering
2 answers:
torisob [31]3 years ago
5 0

Answer:

Explanation:

Given:

Tooth Number, N = 24  

Diametral pitch pd = 12

pitch diameter, d = N/pd = 24/12 = 2in

circular pitch, pc = π/pd  = 3.142/12 = 0.2618in

Addendum, a  = 1/pd = 1/12 =0.08333in

Dedendum, b = 1.25/pd = 0.10417in

Tooth thickness, t = 0.5pc = 0,5 * 0.2618  = 0.1309in

Clearance, c = 0.25/pd = 0.25/12 = 0.02083in

Oduvanchick [21]3 years ago
4 0

Answer:

• Pitch diameter = 2.0000in

• Circular pitch = 0.2618in

• Addendum = 0.0833in

• Dedendum = 0.1042in

• Tooth thickness = 0.1309 in

• Clearance = 0.02083 in

Explanation:

We are given:

Total number, N = 24

Diametral pitch, pd = 12 in

•to calculate pitch diameter, we use:

d = \frac{N}{pd} =\frac{24}{12} = 2.0000 in

•to calculate circular pitch, we have:

P_c= \frac{pi}{pd} = P_c = \frac{3.142}{12}= 0.2618in

•To calculate addendum:

Addendum, a= \frac{1.0000}{pd} => \frac{1.0000}{12} = 0.0833in

•Dedendum:

b= \frac{1.2500}{pd}=> \frac{1.2500}{12} =0.1042in

•Tooth thickness, t :

t = 0.5*pc

= 0.5*0.2618 = 0.1309in

•Clearance, c:

c = \frac{0.2500}{pd} => \frac{0.2500}{12} = 0.2083in

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A budding electronics hobbyist wants to make a simple 1.0-nF capacitor for tuning her crystal radio, using two sheets of aluminu
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Answer:

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c. To keep a 1.0-nF, a larger area of Teflon is required.

Explanation:

a.

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This is given by

d = Kε0A/C

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A = Area = 22 * 28 = 616cm² = 0.0616m²

C = 1.0-nF = 1 * 10^-12F

So, d = (3 * 8.854 * 10^-12 C²/Nm² * 0.0616) / (1 * 10^-12F)

d = 1.64 * 10^-3m

d = 1.64mm

Now, that the distance has been solved.

The Number of Sheets, N is given by

N = d/d,sheet where d, sheet =the sheet thickness = 0.2mm

N = 1.64/0.2

N = 8.2

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b.

Here, she's changed the diameter of the sheets to 12mm

Well make use of the formula in (a) above

Using d = Kε0A/C

Where

d = 12 * 10^-3m

Other constraints remain unchanged

Make A the subject of formula

A = dC/Kε0

A = (12 * 10^-3m * 1 * 10^-12F)/(3 * 8.854 * 10^-12 C²/Nm²)

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A ∝ 1/K

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This means that if she used a Teflon instead, the area will be larger.

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